Solution - Long multiplication
1,600
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | thousands | hundreds | tens | ones |
| 1 | 6 | |||
| × | 1 | 0 | 0 | |
2. Multiply the numbers using long multiplication method
Because the tens digit of the multiplicator equals 0, skip to the next digit.
Proceed by multiplying the hundreds digit (1) of the multiplier (100) by each digit of the multiplicand (16), from right to left.
Because digit (1) is in hundreds place, we shift partial result by 2 place(s) by placing 2 zero(s).
| Place value | thousands | hundreds | tens | ones |
| 1 | 6 | |||
| × | 1 | 0 | 0 | |
| 0 | 0 |
Multiply the hundreds digit (1) of the multiplicator by the number in the ones place value:
1×6=6
Write 6 in the hundreds place.
| Place value | thousands | hundreds | tens | ones |
| 1 | 6 | |||
| × | 1 | 0 | 0 | |
| 6 | 0 | 0 |
Multiply the hundreds digit (1) of the multiplicator by the number in the tens place value:
1×1=1
Write 1 in the thousands place.
| Place value | thousands | hundreds | tens | ones |
| 1 | 6 | |||
| × | 1 | 0 | 0 | |
| 1 | 6 | 0 | 0 |
1,600 is the first partial product.
3. Add the partial products
1600=1600 long addition steps can be seen here
| Place value | thousands | hundreds | tens | ones |
| 1 | 6 | |||
| × | 1 | 0 | 0 | |
| + | 1 | 6 | 0 | 0 |
| 1 | 6 | 0 | 0 |
The solution is: 1,600
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