Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
Place value | ten thousands | thousands | hundreds | tens | ones |
1 | 5 | 0 | 0 | 0 | |
× | 5 | ||||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (5) of the multiplier 5 by each digit of the multiplicand 15,000, from right to left.
Multiply the ones digit (5) of the multiplicator by the number in the ones place value:
5×0=0
Write 0 in the ones place.
Place value | ten thousands | thousands | hundreds | tens | ones |
1 | 5 | 0 | 0 | 0 | |
× | 5 | ||||
0 |
Multiply the ones digit (5) of the multiplicator by the number in the tens place value:
5×0=0
Write 0 in the tens place.
Place value | ten thousands | thousands | hundreds | tens | ones |
1 | 5 | 0 | 0 | 0 | |
× | 5 | ||||
0 | 0 |
Multiply the ones digit (5) of the multiplicator by the number in the hundreds place value:
5×0=0
Write 0 in the hundreds place.
Place value | ten thousands | thousands | hundreds | tens | ones |
1 | 5 | 0 | 0 | 0 | |
× | 5 | ||||
0 | 0 | 0 |
Multiply the ones digit (5) of the multiplicator by the number in the thousands place value:
5×5=25
Write 5 in the thousands place.
Because the result is greater than 9, carry the 2 to the ten thousands place.
Place value | ten thousands | thousands | hundreds | tens | ones |
2 | |||||
1 | 5 | 0 | 0 | 0 | |
× | 5 | ||||
5 | 0 | 0 | 0 |
Multiply the ones digit (5) of the multiplicator by the number in the ten thousands place value and add the carried number (2):
5×1+2=7
Write 7 in the ten thousands place.
Place value | ten thousands | thousands | hundreds | tens | ones |
2 | |||||
1 | 5 | 0 | 0 | 0 | |
× | 5 | ||||
7 | 5 | 0 | 0 | 0 |
The solution is: 75,000
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