Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 3 | 6 | ||||
| × | 1 | 6 | 0 | 0 | ||
2. Multiply the numbers using long multiplication method
Because the tens digit of the multiplicator equals 0, skip to the next digit.
Proceed by multiplying the hundreds digit (6) of the multiplier (1,600) by each digit of the multiplicand (136), from right to left.
Because digit (6) is in hundreds place, we shift partial result by 2 place(s) by placing 2 zero(s).
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 3 | 6 | ||||
| × | 1 | 6 | 0 | 0 | ||
| 0 | 0 | |||||
Multiply the hundreds digit (6) of the multiplicator by the number in the ones place value:
6×6=36
Write 6 in the hundreds place.
Because the result is greater than 9, carry the 3 to the thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 3 | ||||||
| 1 | 3 | 6 | ||||
| × | 1 | 6 | 0 | 0 | ||
| 6 | 0 | 0 | ||||
Multiply the hundreds digit (6) of the multiplicator by the number in the tens place value and add the carried number (3):
6×3+3=21
Write 1 in the thousands place.
Because the result is greater than 9, carry the 2 to the ten thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 2 | 3 | |||||
| 1 | 3 | 6 | ||||
| × | 1 | 6 | 0 | 0 | ||
| 1 | 6 | 0 | 0 | |||
Multiply the hundreds digit (6) of the multiplicator by the number in the hundreds place value and add the carried number (2):
6×1+2=8
Write 8 in the ten thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 2 | 3 | |||||
| 1 | 3 | 6 | ||||
| × | 1 | 6 | 0 | 0 | ||
| 8 | 1 | 6 | 0 | 0 | ||
81,600 is the first partial product.
Proceed by multiplying the thousands digit (1) of the multiplier (1,600) by each digit of the multiplicand (136), from right to left.
Because digit (1) is in thousands place, we shift partial result by 3 place(s) by placing 3 zero(s).
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 3 | 6 | ||||
| × | 1 | 6 | 0 | 0 | ||
| 8 | 1 | 6 | 0 | 0 | ||
| 0 | 0 | 0 |
Multiply the thousands digit (1) of the multiplicator by the number in the ones place value:
1×6=6
Write 6 in the thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 3 | 6 | ||||
| × | 1 | 6 | 0 | 0 | ||
| 8 | 1 | 6 | 0 | 0 | ||
| 6 | 0 | 0 | 0 |
Multiply the thousands digit (1) of the multiplicator by the number in the tens place value:
1×3=3
Write 3 in the ten thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 3 | 6 | ||||
| × | 1 | 6 | 0 | 0 | ||
| 8 | 1 | 6 | 0 | 0 | ||
| 3 | 6 | 0 | 0 | 0 |
Multiply the thousands digit (1) of the multiplicator by the number in the hundreds place value:
1×1=1
Write 1 in the hundred thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 3 | 6 | ||||
| × | 1 | 6 | 0 | 0 | ||
| 8 | 1 | 6 | 0 | 0 | ||
| 1 | 3 | 6 | 0 | 0 | 0 |
136,000 is the second partial product.
3. Add the partial products
81600+136000=217600 long addition steps can be seen here
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 3 | 6 | ||||
| × | 1 | 6 | 0 | 0 | ||
| 8 | 1 | 6 | 0 | 0 | ||
| + | 1 | 3 | 6 | 0 | 0 | 0 |
| 2 | 1 | 7 | 6 | 0 | 0 |
The solution is: 217,600
How did we do?
Please leave us feedback.