Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | hundreds | tens | ones |
| 1 | 3 | 5 | |
| × | 3 | ||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (3) of the multiplier 3 by each digit of the multiplicand 135, from right to left.
Multiply the ones digit (3) of the multiplicator by the number in the ones place value:
3×5=15
Write 5 in the ones place.
Because the result is greater than 9, carry the 1 to the tens place.
| Place value | hundreds | tens | ones |
| 1 | |||
| 1 | 3 | 5 | |
| × | 3 | ||
| 5 |
Multiply the ones digit (3) of the multiplicator by the number in the tens place value and add the carried number (1):
3×3+1=10
Write 0 in the tens place.
Because the result is greater than 9, carry the 1 to the hundreds place.
| Place value | hundreds | tens | ones |
| 1 | 1 | ||
| 1 | 3 | 5 | |
| × | 3 | ||
| 0 | 5 |
Multiply the ones digit (3) of the multiplicator by the number in the hundreds place value and add the carried number (1):
3×1+1=4
Write 4 in the hundreds place.
| Place value | hundreds | tens | ones |
| 1 | 1 | ||
| 1 | 3 | 5 | |
| × | 3 | ||
| 4 | 0 | 5 |
The solution is: 405
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