Solution - Long multiplication

Start by multiplying the ones digit (1) of the multiplier 31 by each digit of the multiplicand 10,000, from right to left.

Multiply the ones digit (1) of the multiplicator by the number in the ones place value:
1×0=0

Write 0 in the ones place.

Multiply the ones digit (1) of the multiplicator by the number in the tens place value:
1×0=0

Write 0 in the tens place.

Multiply the ones digit (1) of the multiplicator by the number in the hundreds place value:
1×0=0

Write 0 in the hundreds place.

Multiply the ones digit (1) of the multiplicator by the number in the thousands place value:
1×0=0

Write 0 in the thousands place.

Multiply the ones digit (1) of the multiplicator by the number in the ten thousands place value:
1×1=1

Write 1 in the ten thousands place.

10,000 is the first partial product.

Proceed by multiplying the tens digit (3) of the multiplier (31) by each digit of the multiplicand (10,000), from right to left.

Because digit (3) is in tens place, we shift partial result by 1 place(s) by placing 1 zero(s).

Multiply the tens digit (3) of the multiplicator by the number in the ones place value:
3×0=0

Write 0 in the tens place.

Multiply the tens digit (3) of the multiplicator by the number in the tens place value:
3×0=0

Write 0 in the hundreds place.

Multiply the tens digit (3) of the multiplicator by the number in the hundreds place value:
3×0=0

Write 0 in the thousands place.

Multiply the tens digit (3) of the multiplicator by the number in the thousands place value:
3×0=0

Write 0 in the ten thousands place.

Multiply the tens digit (3) of the multiplicator by the number in the ten thousands place value:
3×1=3

Write 3 in the hundred thousands place.

300,000 is the second partial product.

10000+300000=310000 long addition steps can be seen here

The solution is: 310,000