Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | ones | . | tenths | hundredths | thousandths |
| 1 | . | 4 | 1 | 7 | |
| × | 0 | . | 1 | ||
| . |
Ignore the decimal points and multiply as if these are whole numbers (as if each most right digit is the ones digit):
In this case we removed 4 decimal place(s). So once calculated, the result will be reduced by the factor of 10,000.
| Place value | thousands | hundreds | tens | ones |
| 1 | 4 | 1 | 7 | |
| × | 1 | |||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (1) of the multiplier 1 by each digit of the multiplicand 1,417, from right to left.
Multiply the ones digit (1) of the multiplicator by the number in the ones place value:
1×7=7
Write 7 in the ones place.
| Place value | thousands | hundreds | tens | ones |
| 1 | 4 | 1 | 7 | |
| × | 1 | |||
| 7 |
Multiply the ones digit (1) of the multiplicator by the number in the tens place value:
1×1=1
Write 1 in the tens place.
| Place value | thousands | hundreds | tens | ones |
| 1 | 4 | 1 | 7 | |
| × | 1 | |||
| 1 | 7 |
Multiply the ones digit (1) of the multiplicator by the number in the hundreds place value:
1×4=4
Write 4 in the hundreds place.
| Place value | thousands | hundreds | tens | ones |
| 1 | 4 | 1 | 7 | |
| × | 1 | |||
| 4 | 1 | 7 |
3. Add the partial products
Multiply the ones digit (1) of the multiplicator by the number in the thousands place value:
1×1=1
Write 1 in the thousands place.
| Place value | thousands | hundreds | tens | ones |
| 1 | 4 | 1 | 7 | |
| × | 1 | |||
| 1 | 4 | 1 | 7 |
Because we have 4 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 4 time(s) to the left (reducing the result by the factor of 10,000) to get the final result:
The solution is: 0.1417
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