Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | ones | . | tenths | hundredths |
| 0 | . | 4 | 3 | |
| × | 0 | . | 0 | 9 |
| . |
Ignore the decimal points and multiply as if these are whole numbers (as if each most right digit is the ones digit):
In this case we removed 4 decimal place(s). So once calculated, the result will be reduced by the factor of 10,000.
| Place value | hundreds | tens | ones |
| 4 | 3 | ||
| × | 9 | ||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (9) of the multiplier 9 by each digit of the multiplicand 43, from right to left.
Multiply the ones digit (9) of the multiplicator by the number in the ones place value:
9×3=27
Write 7 in the ones place.
Because the result is greater than 9, carry the 2 to the tens place.
| Place value | hundreds | tens | ones |
| 2 | |||
| 4 | 3 | ||
| × | 9 | ||
| 7 |
3. Add the partial products
Multiply the ones digit (9) of the multiplicator by the number in the tens place value and add the carried number (2):
9×4+2=38
Write 8 in the tens place.
Because the result is greater than 9, carry the 3 to the hundreds place.
| Place value | hundreds | tens | ones |
| 3 | 2 | ||
| 4 | 3 | ||
| × | 9 | ||
| 3 | 8 | 7 |
Because we have 4 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 4 time(s) to the left (reducing the result by the factor of 10,000) to get the final result:
The solution is: 0.0387
How did we do?
Please leave us feedback.