Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | ones | . | tenths | hundredths | thousandths |
| 0 | . | 0 | 0 | 3 | |
| × | 0 | . | 0 | 0 | 4 |
| . |
Ignore the decimal points and multiply as if these are whole numbers (as if each most right digit is the ones digit):
In this case we removed 6 decimal place(s). So once calculated, the result will be reduced by the factor of 1,000,000.
| Place value | tens | ones |
| 3 | ||
| × | 4 | |
2. Add the partial products
Start by multiplying the ones digit (4) of the multiplier 4 by each digit of the multiplicand 3, from right to left.
Multiply the ones digit (4) of the multiplicator by the number in the ones place value:
4×3=12
Write 2 in the ones place.
Because the result is greater than 9, carry the 1 to the tens place.
| Place value | tens | ones |
| 1 | ||
| 3 | ||
| × | 4 | |
| 1 | 2 |
Because we have 6 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 6 time(s) to the left (reducing the result by the factor of 1,000,000) to get the final result:
The solution is: 0.000012
How did we do?
Please leave us feedback.