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Solution - Geometric Sequences

The common ratio is:

r = 12.913312693498453

r=12.913312693498453

The sum of this series is:

s = 4494

s=4494

The general form of this series is:

a_{n} = 323 \cdot {12.913312693498453}^{n - 1}

a_n=323*12.913312693498453^(n-1)

The nth term of this series is:

323, 4171, 53861.427244582046, 695529.4521274049, 8981589.30285884, 115982071.15239699, 1497712751.6304886, 19340433086.844486, 249749060078.10638, 3225087707695.919

323,4171,53861.427244582046,695529.4521274049,8981589.30285884,115982071.15239699,1497712751.6304886,19340433086.844486,249749060078.10638,3225087707695.919

See steps

Step-by-step explanation

1. Find the common ratio

Find the common ratio by dividing any term in the sequence by the term that comes before it:

$a_{2} a_{1} = \frac{4171}{323} = 12.913312693498453$

The common ratio ( $r$ ) of the sequence is constant and equals the quotient of two consecutive terms.
$r = 12.913312693498453$

2. Find the sum

5 additional steps

$s_{n} = a * ((1 - r^{n}) / (1 - r))$

To find the sum of the series, plug the first term: $a = 323$ , the common ratio: $r = 12.913312693498453$ , and the number of elements $n = 2$ into the geometric series sum formula:

$s_{2} = 323 * ((1 - {12.913312693498453}^{2}) / (1 - 12.913312693498453))$

$s_{2} = 323 * ((1 - 166.75364472006825) / (1 - 12.913312693498453))$

$s_{2} = 323 * (- 165.75364472006825 / (1 - 12.913312693498453))$

$s_{2} = 323 * (- 165.75364472006825 / - 11.913312693498453)$

$s_{2} = 323 \cdot 13.913312693498451$

$s_{2} = 4494$

3. Find the general form

$a_{n} = a \cdot r^{n - 1}$

To find the general form of the series, plug the first term: $a = 323$ and the common ratio: $r = 12.913312693498453$ into the formula for geometric series:

$a_{n} = 323 \cdot {12.913312693498453}^{n - 1}$

4. Find the nth term

Use the general form to find the nth term

$a_{1} = 323$

$a_{2} = a_{1} \cdot r^{n - 1} = 323 \cdot {12.913312693498453}^{2 - 1} = 323 \cdot {12.913312693498453}^{1} = 323 \cdot 12.913312693498453 = 4171$

$a_{3} = a_{1} \cdot r^{n - 1} = 323 \cdot {12.913312693498453}^{3 - 1} = 323 \cdot {12.913312693498453}^{2} = 323 \cdot 166.75364472006825 = 53861.427244582046$

$a_{4} = a_{1} \cdot r^{n - 1} = 323 \cdot {12.913312693498453}^{4 - 1} = 323 \cdot {12.913312693498453}^{3} = 323 \cdot 2153.341957050789 = 695529.4521274049$

$a_{5} = a_{1} \cdot r^{n - 1} = 323 \cdot {12.913312693498453}^{5 - 1} = 323 \cdot {12.913312693498453}^{4} = 323 \cdot 27806.77802742675 = 8981589.30285884$

$a_{6} = a_{1} \cdot r^{n - 1} = 323 \cdot {12.913312693498453}^{6 - 1} = 323 \cdot {12.913312693498453}^{5} = 323 \cdot 359077.61966686376 = 115982071.15239699$

$a_{7} = a_{1} \cdot r^{n - 1} = 323 \cdot {12.913312693498453}^{7 - 1} = 323 \cdot {12.913312693498453}^{6} = 323 \cdot 4636881.583995321 = 1497712751.6304886$

$a_{8} = a_{1} \cdot r^{n - 1} = 323 \cdot {12.913312693498453}^{8 - 1} = 323 \cdot {12.913312693498453}^{7} = 323 \cdot 59877501.81685599 = 19340433086.844486$

$a_{9} = a_{1} \cdot r^{n - 1} = 323 \cdot {12.913312693498453}^{9 - 1} = 323 \cdot {12.913312693498453}^{8} = 323 \cdot 773216904.2665832 = 249749060078.10638$

$a_{10} = a_{1} \cdot r^{n - 1} = 323 \cdot {12.913312693498453}^{10 - 1} = 323 \cdot {12.913312693498453}^{9} = 323 \cdot 9984791664.693247 = 3225087707695.919$

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Why learn this

Geometric sequences are commonly used to explain concepts in mathematics, physics, engineering, biology, economics, computer science, finance, and more, making them a very useful tool to have in our toolkits. One of the most common applications of geometric sequences, for example, is calculating earned or unpaid compound interest, an activity most commonly associated with finance that could mean earning or losing a lot of money! Other applications include, but are certainly not limited to, calculating probability, measuring radioactivity over time, and designing buildings.

Terms and topics

Geometric Sequences