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Solution - Derivative

2 \cos (2 x + 3333)

2 \cos{\left(2 x + 3333 \right)}

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Step-by-step explanation

1. Solve derivative

2 additional steps

Computing the derivative of a sine function using the chain rule.

$\frac{d}{d x} [\sin (2 x + 3333)] = \cos (2 x + 3333) \times \frac{d}{d x} [2 x + 3333]$

Decomposing the function for the chain rule.

$\frac{d}{d x} [\sin (2 x + 3333)] = \frac{d}{d x} [\sin (x)] \times \frac{d}{d x} [2 x + 3333]$

Computing the derivative of a sine function.

$\frac{d}{d x} [\sin (x)] \times \frac{d}{d x} [2 x + 3333] = \cos (x) \times \frac{d}{d x} [2 x + 3333]$

Substituting the variable back into the function.

$\cos (x) \times \frac{d}{d x} [2 x + 3333] = \cos (2 x + 3333) \times \frac{d}{d x} [2 x + 3333]$

Applying the sum rule of derivatives.

$\cos (2 x + 3333) \times \frac{d}{d x} [2 x + 3333] = \cos (2 x + 3333) \times (\frac{d}{d x} [2 x] + \frac{d}{d x} [3333])$

Applying the product rule of derivatives.

$\cos (2 x + 3333) \times (\frac{d}{d x} [2 x] + \frac{d}{d x} [3333]) = \cos (2 x + 3333) \times ((\frac{d}{d x} [2] \times x + 2 \times \frac{d}{d x} [x]) + \frac{d}{d x} [3333])$

The derivative of a constant value is always zero.

$\cos (2 x + 3333) \times ((\frac{d}{d x} [2] \times x + 2 \times \frac{d}{d x} [x]) + \frac{d}{d x} [3333]) = \cos (2 x + 3333) \times ((0 x + 2 \times \frac{d}{d x} [x]) + \frac{d}{d x} [3333])$

Multiplying a number by zero always results in zero.

$\cos (2 x + 3333) \times ((0 x + 2 \times \frac{d}{d x} [x]) + \frac{d}{d x} [3333]) = \cos (2 x + 3333) \times ((0 + 2 \times \frac{d}{d x} [x]) + \frac{d}{d x} [3333])$

Adding zero to a number, which does not change its value.

$\cos (2 x + 3333) \times ((0 + 2 \times \frac{d}{d x} [x]) + \frac{d}{d x} [3333]) = \cos (2 x + 3333) \times (2 \times \frac{d}{d x} [x] + \frac{d}{d x} [3333])$

The derivative of a variable with respect to itself is always equal to one.

$\cos (2 x + 3333) \times (2 \times \frac{d}{d x} [x] + \frac{d}{d x} [3333]) = \cos (2 x + 3333) \times (2 \times 1 + \frac{d}{d x} [3333])$

Multiplying a number by one, which does not change its value.

$\cos (2 x + 3333) \times (2 \times 1 + \frac{d}{d x} [3333]) = \cos (2 x + 3333) \times (2 + \frac{d}{d x} [3333])$

The derivative of a constant value is always zero.

$\cos (2 x + 3333) \times (2 + \frac{d}{d x} [3333]) = \cos (2 x + 3333) \times (2 + 0)$

Adding zero to a number, which does not change its value.

$\cos (2 x + 3333) \times (2 + 0) = \cos (2 x + 3333) \times 2$

Simplifying the arithmetic expressions.

$\cos (2 x + 3333) \times 2 = 2 \cos (2 x + 3333)$

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Why learn this

Ever wondered how to predict the future? Derivatives are your crystal ball!

Picture this: You're a surfer trying to catch the biggest wave. How do you know when it's coming? Derivatives can tell you when it's at its highest point!

Rocket Science: Planning to launch a rocket to Mars? Derivatives tell us the optimal fuel burn rate to minimize fuel consumption and maximize distance!

Stock Market: Trading in the stock market? Derivatives can indicate the rate at which stock prices are changing, helping predict the best time to buy or sell.

Animation: Love animated movies? Artists use derivatives to smoothly change the motion and expressions of characters, making them feel more lifelike.

Engineering: Designing a bridge or a skyscraper? Derivatives help determine the rates of stress and strain changes in materials, ensuring the safety of your structures.

In short, derivatives are like a secret code to understanding change and making predictions in real life. So let's crack this code together and become masters of our futures!

Terms and topics

Derivative

Solution - Derivative

Step-by-step explanation

1. Solve derivative

Why learn this

Terms and topics

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