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Solution - Derivative

nxn-1+-1×ddx[n](n+1)2
n x^{n - 1}+\frac{-1\times \frac{d}{dx}[n]}{\left(n + 1\right)^{2}}

Other Ways to Solve

Derivative

Step-by-step explanation

1. Solve derivative

Applying the sum rule of derivatives.

ddx[xn+1n+1]=ddx[xn]+ddx[1n+1]

Computing the derivative of x raised to the power of n.

ddx[xn]+ddx[1n+1]=nxn-1+ddx[1n+1]

Computing the derivative of a fraction.

nxn-1+ddx[1n+1]=nxn-1+ddx[1]×(n+1)-1×ddx[n+1](n+1)2

The derivative of a constant value is always zero.

nxn-1+ddx[1]×(n+1)-1×ddx[n+1](n+1)2=nxn-1+0(n+1)-1×ddx[n+1](n+1)2

Applying the sum rule of derivatives.

nxn-1+0×(n+1)-1×ddx[n+1](n+1)2=nxn-1+0×(n+1)-1(ddx[n]+ddx[1])(n+1)2

Multiplying a number by zero always results in zero.

nxn-1+0×(n+1)-1(ddx[n]+ddx[1])(n+1)2=nxn-1+0-1(ddx[n]+ddx[1])(n+1)2

The derivative of a constant value is always zero.

nxn-1+0-1(ddx[n]+ddx[1])(n+1)2=nxn-1+0-1(ddx[n]+0)(n+1)2

Adding zero to a number, which does not change its value.

nxn-1+0-1(ddx[n]+0)(n+1)2=nxn-1+-1(ddx[n]+0)(n+1)2

Adding zero to a number, which does not change its value.

nxn-1+-1(ddx[n]+0)(n+1)2=nxn-1+-1×ddx[n](n+1)2

Why learn this

Ever wondered how to predict the future? Derivatives are your crystal ball!

Picture this: You're a surfer trying to catch the biggest wave. How do you know when it's coming? Derivatives can tell you when it's at its highest point!

Rocket Science: Planning to launch a rocket to Mars? Derivatives tell us the optimal fuel burn rate to minimize fuel consumption and maximize distance!

Stock Market: Trading in the stock market? Derivatives can indicate the rate at which stock prices are changing, helping predict the best time to buy or sell.

Animation: Love animated movies? Artists use derivatives to smoothly change the motion and expressions of characters, making them feel more lifelike.

Engineering: Designing a bridge or a skyscraper? Derivatives help determine the rates of stress and strain changes in materials, ensuring the safety of your structures.

In short, derivatives are like a secret code to understanding change and making predictions in real life. So let's crack this code together and become masters of our futures!

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