Solution - Derivative

\cos (x y^{2}) \times (y^{2} + x \times (y^{2} \times (\frac{2}{y} \times \frac{d}{d x} [y])))

\cos{\left(x y^{2} \right)}\times (y^{2}+x\times (y^{2}\times (\frac{2}{y}\times \frac{d}{dx}[y])))

See steps

Step-by-step explanation

1. Solve derivative

2 additional steps

Computing the derivative of a sine function using the chain rule.

$\frac{d}{d x} [\sin (x y^{2})] = \cos (x y^{2}) \times \frac{d}{d x} [x y^{2}]$

Decomposing the function for the chain rule.

$\frac{d}{d x} [\sin (x y^{2})] = \frac{d}{d x} [\sin (x)] \times \frac{d}{d x} [x y^{2}]$

Computing the derivative of a sine function.

$\frac{d}{d x} [\sin (x)] \times \frac{d}{d x} [x y^{2}] = \cos (x) \times \frac{d}{d x} [x y^{2}]$

Substituting the variable back into the function.

$\cos (x) \times \frac{d}{d x} [x y^{2}] = \cos (x y^{2}) \times \frac{d}{d x} [x y^{2}]$

Applying the product rule of derivatives.

$\cos (x y^{2}) \times \frac{d}{d x} [x y^{2}] = \cos (x y^{2}) \times (\frac{d}{d x} [x] \times y^{2} + x \times \frac{d}{d x} [y^{2}])$

The derivative of a variable with respect to itself is always equal to one.

$\cos (x y^{2}) \times (\frac{d}{d x} [x] \times y^{2} + x \times \frac{d}{d x} [y^{2}]) = \cos (x y^{2}) \times (1 y^{2} + x \times \frac{d}{d x} [y^{2}])$

Computing the derivative of a power function.

$\cos (x y^{2}) \times (1 y^{2} + x \times \frac{d}{d x} [y^{2}]) = \cos (x y^{2}) \times (1 y^{2} + x \times (y^{2} (\frac{d}{d x} [2] \times \ln (y) + \frac{2}{y} \times \frac{d}{d x} [y])))$

Multiplying a number by one, which does not change its value.

$\cos (x y^{2}) \times (1 y^{2} + x \times (y^{2} (\frac{d}{d x} [2] \times \ln (y) + \frac{2}{y} \times \frac{d}{d x} [y]))) = \cos (x y^{2}) \times (y^{2} + x \times (y^{2} (\frac{d}{d x} [2] \times \ln (y) + \frac{2}{y} \times \frac{d}{d x} [y])))$

The derivative of a constant value is always zero.

$\cos (x y^{2}) \times (y^{2} + x \times (y^{2} (\frac{d}{d x} [2] \times \ln (y) + \frac{2}{y} \times \frac{d}{d x} [y]))) = \cos (x y^{2}) \times (y^{2} + x \times (y^{2} (0 \times \ln (y) + \frac{2}{y} \times \frac{d}{d x} [y])))$

Multiplying a number by zero always results in zero.

$\cos (x y^{2}) \times (y^{2} + x \times (y^{2} (0 \times \ln (y) + \frac{2}{y} \times \frac{d}{d x} [y]))) = \cos (x y^{2}) \times (y^{2} + x \times (y^{2} (0 + \frac{2}{y} \times \frac{d}{d x} [y])))$

Adding zero to a number, which does not change its value.

$\cos (x y^{2}) \times (y^{2} + x \times (y^{2} (0 + \frac{2}{y} \times \frac{d}{d x} [y]))) = \cos (x y^{2}) \times (y^{2} + x \times (y^{2} \times (\frac{2}{y} \times \frac{d}{d x} [y])))$

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Why learn this

Ever wondered how to predict the future? Derivatives are your crystal ball!

Picture this: You're a surfer trying to catch the biggest wave. How do you know when it's coming? Derivatives can tell you when it's at its highest point!

Rocket Science: Planning to launch a rocket to Mars? Derivatives tell us the optimal fuel burn rate to minimize fuel consumption and maximize distance!

Stock Market: Trading in the stock market? Derivatives can indicate the rate at which stock prices are changing, helping predict the best time to buy or sell.

Animation: Love animated movies? Artists use derivatives to smoothly change the motion and expressions of characters, making them feel more lifelike.

Engineering: Designing a bridge or a skyscraper? Derivatives help determine the rates of stress and strain changes in materials, ensuring the safety of your structures.

In short, derivatives are like a secret code to understanding change and making predictions in real life. So let's crack this code together and become masters of our futures!

Terms and topics

Derivative

Solution - Derivative

Step-by-step explanation

1. Solve derivative

Why learn this

Terms and topics

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