Solution - Derivative

- \frac{5 \ln (x)}{x^{2}} + \frac{5}{x^{2}}

- \frac{5 \ln{\left(x \right)}}{x^{2}}+\frac{5}{x^{2}}

See steps

Step-by-step explanation

1. Solve derivative

Applying the product rule of derivatives.

$\frac{d}{d x} [\frac{5}{x} \times \ln (x)] = \frac{d}{d x} [\frac{5}{x}] \times \ln (x) + \frac{5}{x} \times \frac{d}{d x} [\ln (x)]$

Computing the derivative of a fraction.

$\frac{d}{d x} [\frac{5}{x}] \times \ln (x) + \frac{5}{x} \times \frac{d}{d x} [\ln (x)] = \frac{\frac{d}{d x} [5] \times x - 5 \times \frac{d}{d x} [x]}{x^{2}} \times \ln (x) + \frac{5}{x} \times \frac{d}{d x} [\ln (x)]$

Computing the derivative of a natural logarithm function.

$\frac{\frac{d}{d x} [5] \times x - 5 \times \frac{d}{d x} [x]}{x^{2}} \times \ln (x) + \frac{5}{x} \times \frac{d}{d x} [\ln (x)] = \frac{\frac{d}{d x} [5] \times x - 5 \times \frac{d}{d x} [x]}{x^{2}} \times \ln (x) + \frac{5}{x} \times \frac{1}{x}$

The derivative of a constant value is always zero.

$\frac{\frac{d}{d x} [5] \times x - 5 \times \frac{d}{d x} [x]}{x^{2}} \times \ln (x) + \frac{5}{x} \times \frac{1}{x} = \frac{0 x - 5 \times \frac{d}{d x} [x]}{x^{2}} \times \ln (x) + \frac{5}{x} \times \frac{1}{x}$

The derivative of a variable with respect to itself is always equal to one.

$\frac{0 x - 5 \times \frac{d}{d x} [x]}{x^{2}} \times \ln (x) + \frac{5}{x} \times \frac{1}{x} = \frac{0 x - 5 \times 1}{x^{2}} \times \ln (x) + \frac{5}{x} \times \frac{1}{x}$

Multiplying a number by zero always results in zero.

$\frac{0 x - 5 \times 1}{x^{2}} \times \ln (x) + \frac{5}{x} \div x = \frac{0 - 5 \times 1}{x^{2}} \times \ln (x) + \frac{5}{x} \div x$

Multiplying a number by one, which does not change its value.

$\frac{0 - 5 \times 1}{x^{2}} \times \ln (x) + \frac{5}{x} \div x = \frac{0 - 5}{x^{2}} \times \ln (x) + \frac{5}{x} \div x$

Simplifying the arithmetic expressions.

$\frac{0 - 5}{x^{2}} \times \ln (x) + \frac{5}{x} \div x = \frac{0 - 5}{x^{2}} \times \ln (x) + \frac{5}{x^{2}}$

Adding zero to a number, which does not change its value.

$\frac{0 - 5}{x^{2}} \times \ln (x) + \frac{5}{x^{2}} = \frac{- 5}{x^{2}} \times \ln (x) + \frac{5}{x^{2}}$

Simplifying the arithmetic expressions.

$\frac{- 5}{x^{2}} \times \ln (x) + \frac{5}{x^{2}} = - \frac{5}{x^{2}} \times \ln (x) + \frac{5}{x^{2}}$

Simplifying the arithmetic expressions.

$- \frac{5}{x^{2}} \times \ln (x) + \frac{5}{x^{2}} = - \frac{5 \ln (x)}{x^{2}} + \frac{5}{x^{2}}$

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Why learn this

Ever wondered how to predict the future? Derivatives are your crystal ball!

Picture this: You're a surfer trying to catch the biggest wave. How do you know when it's coming? Derivatives can tell you when it's at its highest point!

Rocket Science: Planning to launch a rocket to Mars? Derivatives tell us the optimal fuel burn rate to minimize fuel consumption and maximize distance!

Stock Market: Trading in the stock market? Derivatives can indicate the rate at which stock prices are changing, helping predict the best time to buy or sell.

Animation: Love animated movies? Artists use derivatives to smoothly change the motion and expressions of characters, making them feel more lifelike.

Engineering: Designing a bridge or a skyscraper? Derivatives help determine the rates of stress and strain changes in materials, ensuring the safety of your structures.

In short, derivatives are like a secret code to understanding change and making predictions in real life. So let's crack this code together and become masters of our futures!

Terms and topics

Derivative

Solution - Derivative

Step-by-step explanation

1. Solve derivative

Why learn this

Terms and topics

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