Solution - Base conversion

3, 791

3,791

Step-by-step explanation

${(E C F)}_{16} = b a s e 10$

Identify the source number, source base, and target base before converting through base 10.

${(E C F)}_{16} = 14 \cdot 16^{2} + 12 \cdot 16^{1} + 15 \cdot 16^{0}$

$14 \cdot 16^{2} + 12 \cdot 16^{1} + 15 \cdot 16^{0} = 3791$

Expand each digit by place value: $14 \cdot 16^{2}$
+ $12 \cdot 16^{1}$
+ $15 \cdot 16^{0}$ . This gives $3, 791$ in base 10.

$\frac{3791}{10} = 379 r e m a \in d e r 1$

$\frac{379}{10} = 37 r e m a \in d e r 9$

$\frac{37}{10} = 3 r e m a \in d e r 7$

$\frac{3}{10} = 0 r e m a \in d e r 3$

$1 \to 9 \to 7 \to 3 = 3791$

$3791 (b a s e 10) = {(3791)}_{10}$

Repeatedly divide $3, 791$ by $10$ , collect remainders, and read them in reverse to get $3, 791$ .

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Base conversion is foundational for computer science, digital systems, and number theory.