Solution - Base conversion

$${\left(7F5\right)}_{16}$$

Expand digits with place-value powers in the source base.

$$7\cdot {16}^2+15\cdot {16}^1+5\cdot {16}^0$$

Sum the expanded terms to obtain the base-10 value.

$$2037$$

Expand each digit by place value: $$7·{16}^2$$
+ $$15·{16}^1$$
+ $$5·{16}^0$$. This gives $$2,037$$ in base 10.

$$2037\left(base10\right)$$

Use repeated division by the target base.

$$\frac{2037}{10}$$

Record quotient and remainder for this division cycle.

$$2037=10\cdot 203+7$$

Record quotient and remainder for this division cycle.

$$203=10\cdot 20+3$$

Record quotient and remainder for this division cycle.

$$20=10\cdot 2+0$$

Record quotient and remainder for this division cycle.

$$2=10\cdot 0+2$$

Read remainders from last to first to form target-base digits.

$$2037$$

Final converted representation in the target base.

$${\left(2037\right)}_{10}$$

Repeatedly divide $$2,037$$ by $$10$$, collect remainders, and read them in reverse to get $$2,037$$.