Solution - Base conversion

$${\left(3E4\right)}_{16}$$

Expand digits with place-value powers in the source base.

$$3\cdot {16}^2+14\cdot {16}^1+4\cdot {16}^0$$

Sum the expanded terms to obtain the base-10 value.

$$996$$

Expand each digit by place value: $$3·{16}^2$$
+ $$14·{16}^1$$
+ $$4·{16}^0$$. This gives $$996$$ in base 10.

$$996\left(base10\right)$$

Use repeated division by the target base.

$$\frac{996}{10}$$

Record quotient and remainder for this division cycle.

$$996=10\cdot 99+6$$

Record quotient and remainder for this division cycle.

$$99=10\cdot 9+9$$

Record quotient and remainder for this division cycle.

$$9=10\cdot 0+9$$

Read remainders from last to first to form target-base digits.

$$996$$

Final converted representation in the target base.

$${\left(996\right)}_{10}$$

Repeatedly divide $$996$$ by $$10$$, collect remainders, and read them in reverse to get $$996$$.