Solution - Base conversion

$${\left(3C6\right)}_{16}$$

Expand digits with place-value powers in the source base.

$$3\cdot {16}^2+12\cdot {16}^1+6\cdot {16}^0$$

Sum the expanded terms to obtain the base-10 value.

$$966$$

Expand each digit by place value: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$6·{16}^0$$. This gives $$966$$ in base 10.

$$966\left(base10\right)$$

Use repeated division by the target base.

$$\frac{966}{10}$$

Record quotient and remainder for this division cycle.

$$966=10\cdot 96+6$$

Record quotient and remainder for this division cycle.

$$96=10\cdot 9+6$$

Record quotient and remainder for this division cycle.

$$9=10\cdot 0+9$$

Read remainders from last to first to form target-base digits.

$$966$$

Final converted representation in the target base.

$${\left(966\right)}_{10}$$

Repeatedly divide $$966$$ by $$10$$, collect remainders, and read them in reverse to get $$966$$.