Solution - Base conversion

737

737

Step-by-step explanation

${(2 E 1)}_{16} = b a s e 10$

Identify the source number, source base, and target base before converting through base 10.

${(2 E 1)}_{16} = 2 \cdot 16^{2} + 14 \cdot 16^{1} + 1 \cdot 16^{0}$

$2 \cdot 16^{2} + 14 \cdot 16^{1} + 1 \cdot 16^{0} = 737$

Expand each digit by place value: $2 \cdot 16^{2}$
+ $14 \cdot 16^{1}$
+ $1 \cdot 16^{0}$ . This gives $737$ in base 10.

$\frac{737}{10} = 73 r e m a \in d e r 7$

$\frac{73}{10} = 7 r e m a \in d e r 3$

$\frac{7}{10} = 0 r e m a \in d e r 7$

$7 \to 3 \to 7 = 737$

$737 (b a s e 10) = {(737)}_{10}$

Repeatedly divide $737$ by $10$ , collect remainders, and read them in reverse to get $737$ .

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Base conversion is foundational for computer science, digital systems, and number theory.