Solution - Base conversion

$${\left(2C5\right)}_{16}$$

Expand digits with place-value powers in the source base.

$$2\cdot {16}^2+12\cdot {16}^1+5\cdot {16}^0$$

Sum the expanded terms to obtain the base-10 value.

$$709$$

Expand each digit by place value: $$2·{16}^2$$
+ $$12·{16}^1$$
+ $$5·{16}^0$$. This gives $$709$$ in base 10.

$$709\left(base10\right)$$

Use repeated division by the target base.

$$\frac{709}{10}$$

Record quotient and remainder for this division cycle.

$$709=10\cdot 70+9$$

Record quotient and remainder for this division cycle.

$$70=10\cdot 7+0$$

Record quotient and remainder for this division cycle.

$$7=10\cdot 0+7$$

Read remainders from last to first to form target-base digits.

$$709$$

Final converted representation in the target base.

$${\left(709\right)}_{10}$$

Repeatedly divide $$709$$ by $$10$$, collect remainders, and read them in reverse to get $$709$$.