Solution - Base conversion

$${\left(1E5\right)}_{16}$$

Expand digits with place-value powers in the source base.

$$1\cdot {16}^2+14\cdot {16}^1+5\cdot {16}^0$$

Sum the expanded terms to obtain the base-10 value.

$$485$$

Expand each digit by place value: $$1·{16}^2$$
+ $$14·{16}^1$$
+ $$5·{16}^0$$. This gives $$485$$ in base 10.

$$485\left(base10\right)$$

Use repeated division by the target base.

$$\frac{485}{10}$$

Record quotient and remainder for this division cycle.

$$485=10\cdot 48+5$$

Record quotient and remainder for this division cycle.

$$48=10\cdot 4+8$$

Record quotient and remainder for this division cycle.

$$4=10\cdot 0+4$$

Read remainders from last to first to form target-base digits.

$$485$$

Final converted representation in the target base.

$${\left(485\right)}_{10}$$

Repeatedly divide $$485$$ by $$10$$, collect remainders, and read them in reverse to get $$485$$.