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Solution - Absolute value equations

Exact form: x=-5,56
x=-5 , \frac{5}{6}
Decimal form: x=5,0.833
x=-5 , 0.833

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

7|x|5|x2|=0

Add 5|x2| to both sides of the equation:

7|x|5|x2|+5|x2|=5|x2|

Simplify the arithmetic

7|x|=5|x2|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
7|x|=5|x2|
without the absolute value bars:

|x|=|y|7|x|=5|x2|
x=+y7(x)=5(x2)
x=y7(x)=5((x2))
+x=y7(x)=5(x2)
x=y7((x))=5(x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|7|x|=5|x2|
x=+y , +x=y7(x)=5(x2)
x=y , x=y7(x)=5((x2))

3. Solve the two equations for x

9 additional steps

7x=5·(x-2)

Expand the parentheses:

7x=5x+5·-2

Simplify the arithmetic:

7x=5x10

Subtract from both sides:

(7x)-5x=(5x-10)-5x

Simplify the arithmetic:

2x=(5x-10)-5x

Group like terms:

2x=(5x-5x)-10

Simplify the arithmetic:

2x=10

Divide both sides by :

(2x)2=-102

Simplify the fraction:

x=-102

Find the greatest common factor of the numerator and denominator:

x=(-5·2)(1·2)

Factor out and cancel the greatest common factor:

x=5

12 additional steps

7x=5·(-(x-2))

Expand the parentheses:

7x=5·(-x+2)

7x=5·-x+5·2

Group like terms:

7x=(5·-1)x+5·2

Multiply the coefficients:

7x=-5x+5·2

Simplify the arithmetic:

7x=5x+10

Add to both sides:

(7x)+5x=(-5x+10)+5x

Simplify the arithmetic:

12x=(-5x+10)+5x

Group like terms:

12x=(-5x+5x)+10

Simplify the arithmetic:

12x=10

Divide both sides by :

(12x)12=1012

Simplify the fraction:

x=1012

Find the greatest common factor of the numerator and denominator:

x=(5·2)(6·2)

Factor out and cancel the greatest common factor:

x=56

4. List the solutions

x=-5,56
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=7|x|
y=5|x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.