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Solution - Absolute value equations

Exact form: y=-452,458
y=-\frac{45}{2} , \frac{45}{8}
Mixed number form: y=-2212,558
y=-22\frac{1}{2} , 5\frac{5}{8}
Decimal form: y=22.5,5.625
y=-22.5 , 5.625

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
5|y|=3|y15|
without the absolute value bars:

|x|=|y|5|y|=3|y15|
x=+y5(y)=3(y15)
x=y5(y)=3((y15))
+x=y5(y)=3(y15)
x=y5((y))=3(y15)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|5|y|=3|y15|
x=+y , +x=y5(y)=3(y15)
x=y , x=y5(y)=3((y15))

2. Solve the two equations for y

7 additional steps

5y=3·(y-15)

Expand the parentheses:

5y=3y+3·-15

Simplify the arithmetic:

5y=3y45

Subtract from both sides:

(5y)-3y=(3y-45)-3y

Simplify the arithmetic:

2y=(3y-45)-3y

Group like terms:

2y=(3y-3y)-45

Simplify the arithmetic:

2y=45

Divide both sides by :

(2y)2=-452

Simplify the fraction:

y=-452

10 additional steps

5y=3·(-(y-15))

Expand the parentheses:

5y=3·(-y+15)

5y=3·-y+3·15

Group like terms:

5y=(3·-1)y+3·15

Multiply the coefficients:

5y=-3y+3·15

Simplify the arithmetic:

5y=3y+45

Add to both sides:

(5y)+3y=(-3y+45)+3y

Simplify the arithmetic:

8y=(-3y+45)+3y

Group like terms:

8y=(-3y+3y)+45

Simplify the arithmetic:

8y=45

Divide both sides by :

(8y)8=458

Simplify the fraction:

y=458

3. List the solutions

y=-452,458
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=5|y|
y=3|y15|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.