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Solution - Absolute value equations

Exact form: x=416,694
x=\frac{41}{6} , \frac{69}{4}
Mixed number form: x=656,1714
x=6\frac{5}{6} , 17\frac{1}{4}
Decimal form: x=6.833,17.25
x=6.833 , 17.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
5|x11|=|x14|
without the absolute value bars:

|x|=|y|5|x11|=|x14|
x=+y5(x11)=(x14)
x=y5(x11)=(x14)
+x=y5(x11)=(x14)
x=y5((x11))=(x14)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|5|x11|=|x14|
x=+y , +x=y5(x11)=(x14)
x=y , x=y5(x11)=(x14)

2. Solve the two equations for x

11 additional steps

5·(x-11)=(-x-14)

Expand the parentheses:

5x+5·-11=(-x-14)

Simplify the arithmetic:

5x-55=(-x-14)

Add to both sides:

(5x-55)+x=(-x-14)+x

Group like terms:

(5x+x)-55=(-x-14)+x

Simplify the arithmetic:

6x-55=(-x-14)+x

Group like terms:

6x-55=(-x+x)-14

Simplify the arithmetic:

6x55=14

Add to both sides:

(6x-55)+55=-14+55

Simplify the arithmetic:

6x=14+55

Simplify the arithmetic:

6x=41

Divide both sides by :

(6x)6=416

Simplify the fraction:

x=416

12 additional steps

5·(x-11)=-(-x-14)

Expand the parentheses:

5x+5·-11=-(-x-14)

Simplify the arithmetic:

5x-55=-(-x-14)

Expand the parentheses:

5x55=x+14

Subtract from both sides:

(5x-55)-x=(x+14)-x

Group like terms:

(5x-x)-55=(x+14)-x

Simplify the arithmetic:

4x-55=(x+14)-x

Group like terms:

4x-55=(x-x)+14

Simplify the arithmetic:

4x55=14

Add to both sides:

(4x-55)+55=14+55

Simplify the arithmetic:

4x=14+55

Simplify the arithmetic:

4x=69

Divide both sides by :

(4x)4=694

Simplify the fraction:

x=694

3. List the solutions

x=416,694
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=5|x11|
y=|x14|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.