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Solution - Absolute value equations

Exact form: x=-12,-1211
x=-12 , -\frac{12}{11}
Mixed number form: x=-12,-1111
x=-12 , -1\frac{1}{11}
Decimal form: x=12,1.091
x=-12 , -1.091

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
5|x|=6|x+2|
without the absolute value bars:

|x|=|y|5|x|=6|x+2|
x=+y5(x)=6(x+2)
x=y5(x)=6((x+2))
+x=y5(x)=6(x+2)
x=y5((x))=6(x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|5|x|=6|x+2|
x=+y , +x=y5(x)=6(x+2)
x=y , x=y5(x)=6((x+2))

2. Solve the two equations for x

8 additional steps

5x=6·(x+2)

Expand the parentheses:

5x=6x+6·2

Simplify the arithmetic:

5x=6x+12

Subtract from both sides:

(5x)-6x=(6x+12)-6x

Simplify the arithmetic:

-x=(6x+12)-6x

Group like terms:

-x=(6x-6x)+12

Simplify the arithmetic:

x=12

Multiply both sides by :

-x·-1=12·-1

Remove the one(s):

x=12·-1

Simplify the arithmetic:

x=12

10 additional steps

5x=6·(-(x+2))

Expand the parentheses:

5x=6·(-x-2)

5x=6·-x+6·-2

Group like terms:

5x=(6·-1)x+6·-2

Multiply the coefficients:

5x=-6x+6·-2

Simplify the arithmetic:

5x=6x12

Add to both sides:

(5x)+6x=(-6x-12)+6x

Simplify the arithmetic:

11x=(-6x-12)+6x

Group like terms:

11x=(-6x+6x)-12

Simplify the arithmetic:

11x=12

Divide both sides by :

(11x)11=-1211

Simplify the fraction:

x=-1211

3. List the solutions

x=-12,-1211
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=5|x|
y=6|x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.