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Solution - Absolute value equations

Exact form: k=3,43
k=3 , \frac{4}{3}
Mixed number form: k=3,113
k=3 , 1\frac{1}{3}
Decimal form: k=3,1.333
k=3 , 1.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
5|k2|=|k+2|
without the absolute value bars:

|x|=|y|5|k2|=|k+2|
x=+y5(k2)=(k+2)
x=y5(k2)=(k+2)
+x=y5(k2)=(k+2)
x=y5((k2))=(k+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|5|k2|=|k+2|
x=+y , +x=y5(k2)=(k+2)
x=y , x=y5(k2)=(k+2)

2. Solve the two equations for k

13 additional steps

5·(k-2)=(k+2)

Expand the parentheses:

5k+5·-2=(k+2)

Simplify the arithmetic:

5k-10=(k+2)

Subtract from both sides:

(5k-10)-k=(k+2)-k

Group like terms:

(5k-k)-10=(k+2)-k

Simplify the arithmetic:

4k-10=(k+2)-k

Group like terms:

4k-10=(k-k)+2

Simplify the arithmetic:

4k10=2

Add to both sides:

(4k-10)+10=2+10

Simplify the arithmetic:

4k=2+10

Simplify the arithmetic:

4k=12

Divide both sides by :

(4k)4=124

Simplify the fraction:

k=124

Find the greatest common factor of the numerator and denominator:

k=(3·4)(1·4)

Factor out and cancel the greatest common factor:

k=3

14 additional steps

5·(k-2)=-(k+2)

Expand the parentheses:

5k+5·-2=-(k+2)

Simplify the arithmetic:

5k-10=-(k+2)

Expand the parentheses:

5k10=k2

Add to both sides:

(5k-10)+k=(-k-2)+k

Group like terms:

(5k+k)-10=(-k-2)+k

Simplify the arithmetic:

6k-10=(-k-2)+k

Group like terms:

6k-10=(-k+k)-2

Simplify the arithmetic:

6k10=2

Add to both sides:

(6k-10)+10=-2+10

Simplify the arithmetic:

6k=2+10

Simplify the arithmetic:

6k=8

Divide both sides by :

(6k)6=86

Simplify the fraction:

k=86

Find the greatest common factor of the numerator and denominator:

k=(4·2)(3·2)

Factor out and cancel the greatest common factor:

k=43

3. List the solutions

k=3,43
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=5|k2|
y=|k+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.