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Solution - Absolute value equations

Exact form: x=179,1311
x=\frac{17}{9} , \frac{13}{11}
Mixed number form: x=189,1211
x=1\frac{8}{9} , 1\frac{2}{11}
Decimal form: x=1.889,1.182
x=1.889 , 1.182

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
5|2x3|=|x+2|
without the absolute value bars:

|x|=|y|5|2x3|=|x+2|
x=+y5(2x3)=(x+2)
x=y5(2x3)=(x+2)
+x=y5(2x3)=(x+2)
x=y5((2x3))=(x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|5|2x3|=|x+2|
x=+y , +x=y5(2x3)=(x+2)
x=y , x=y5(2x3)=(x+2)

2. Solve the two equations for x

12 additional steps

5·(2x-3)=(x+2)

Expand the parentheses:

5·2x+5·-3=(x+2)

Multiply the coefficients:

10x+5·-3=(x+2)

Simplify the arithmetic:

10x-15=(x+2)

Subtract from both sides:

(10x-15)-x=(x+2)-x

Group like terms:

(10x-x)-15=(x+2)-x

Simplify the arithmetic:

9x-15=(x+2)-x

Group like terms:

9x-15=(x-x)+2

Simplify the arithmetic:

9x15=2

Add to both sides:

(9x-15)+15=2+15

Simplify the arithmetic:

9x=2+15

Simplify the arithmetic:

9x=17

Divide both sides by :

(9x)9=179

Simplify the fraction:

x=179

13 additional steps

5·(2x-3)=-(x+2)

Expand the parentheses:

5·2x+5·-3=-(x+2)

Multiply the coefficients:

10x+5·-3=-(x+2)

Simplify the arithmetic:

10x-15=-(x+2)

Expand the parentheses:

10x15=x2

Add to both sides:

(10x-15)+x=(-x-2)+x

Group like terms:

(10x+x)-15=(-x-2)+x

Simplify the arithmetic:

11x-15=(-x-2)+x

Group like terms:

11x-15=(-x+x)-2

Simplify the arithmetic:

11x15=2

Add to both sides:

(11x-15)+15=-2+15

Simplify the arithmetic:

11x=2+15

Simplify the arithmetic:

11x=13

Divide both sides by :

(11x)11=1311

Simplify the fraction:

x=1311

3. List the solutions

x=179,1311
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=5|2x3|
y=|x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.