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Solution - Absolute value equations

Exact form: x=512,-52
x=\frac{5}{12} , -\frac{5}{2}
Mixed number form: x=512,-212
x=\frac{5}{12} , -2\frac{1}{2}
Decimal form: x=0.417,2.5
x=0.417 , -2.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
5|x+1|=|7x|
without the absolute value bars:

|x|=|y|5|x+1|=|7x|
x=+y5(x+1)=(7x)
x=y5(x+1)=(7x)
+x=y5(x+1)=(7x)
x=y5((x+1))=(7x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|5|x+1|=|7x|
x=+y , +x=y5(x+1)=(7x)
x=y , x=y5(x+1)=(7x)

2. Solve the two equations for x

14 additional steps

5·(-x+1)=7x

Expand the parentheses:

5·-x+5·1=7x

Group like terms:

(5·-1)x+5·1=7x

Multiply the coefficients:

-5x+5·1=7x

Simplify the arithmetic:

5x+5=7x

Subtract from both sides:

(-5x+5)-7x=(7x)-7x

Group like terms:

(-5x-7x)+5=(7x)-7x

Simplify the arithmetic:

-12x+5=(7x)-7x

Simplify the arithmetic:

12x+5=0

Subtract from both sides:

(-12x+5)-5=0-5

Simplify the arithmetic:

12x=05

Simplify the arithmetic:

12x=5

Divide both sides by :

(-12x)-12=-5-12

Cancel out the negatives:

12x12=-5-12

Simplify the fraction:

x=-5-12

Cancel out the negatives:

x=512

12 additional steps

5·(-x+1)=-(7x)

Expand the parentheses:

5·-x+5·1=-(7x)

Group like terms:

(5·-1)x+5·1=-(7x)

Multiply the coefficients:

-5x+5·1=-(7x)

Simplify the arithmetic:

-5x+5=-(7x)

Add to both sides:

(-5x+5)+7x=(-7x)+7x

Group like terms:

(-5x+7x)+5=(-7x)+7x

Simplify the arithmetic:

2x+5=(-7x)+7x

Simplify the arithmetic:

2x+5=0

Subtract from both sides:

(2x+5)-5=0-5

Simplify the arithmetic:

2x=05

Simplify the arithmetic:

2x=5

Divide both sides by :

(2x)2=-52

Simplify the fraction:

x=-52

3. List the solutions

x=512,-52
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=5|x+1|
y=|7x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.