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Solution - Absolute value equations

Exact form: x=6,2
x=6 , 2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
4|x3|=|2x|
without the absolute value bars:

|x|=|y|4|x3|=|2x|
x=+y4(x3)=(2x)
x=y4(x3)=(2x)
+x=y4(x3)=(2x)
x=y4((x3))=(2x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|4|x3|=|2x|
x=+y , +x=y4(x3)=(2x)
x=y , x=y4(x3)=(2x)

2. Solve the two equations for x

12 additional steps

4·(x-3)=2x

Expand the parentheses:

4x+4·-3=2x

Simplify the arithmetic:

4x12=2x

Subtract from both sides:

(4x-12)-2x=(2x)-2x

Group like terms:

(4x-2x)-12=(2x)-2x

Simplify the arithmetic:

2x-12=(2x)-2x

Simplify the arithmetic:

2x12=0

Add to both sides:

(2x-12)+12=0+12

Simplify the arithmetic:

2x=0+12

Simplify the arithmetic:

2x=12

Divide both sides by :

(2x)2=122

Simplify the fraction:

x=122

Find the greatest common factor of the numerator and denominator:

x=(6·2)(1·2)

Factor out and cancel the greatest common factor:

x=6

12 additional steps

4·(x-3)=-(2x)

Expand the parentheses:

4x+4·-3=-(2x)

Simplify the arithmetic:

4x-12=-(2x)

Add to both sides:

(4x-12)+2x=(-2x)+2x

Group like terms:

(4x+2x)-12=(-2x)+2x

Simplify the arithmetic:

6x-12=(-2x)+2x

Simplify the arithmetic:

6x12=0

Add to both sides:

(6x-12)+12=0+12

Simplify the arithmetic:

6x=0+12

Simplify the arithmetic:

6x=12

Divide both sides by :

(6x)6=126

Simplify the fraction:

x=126

Find the greatest common factor of the numerator and denominator:

x=(2·6)(1·6)

Factor out and cancel the greatest common factor:

x=2

3. List the solutions

x=6,2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=4|x3|
y=|2x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.