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Solution - Absolute value equations

Exact form: x=4,43
x=4 , \frac{4}{3}
Mixed number form: x=4,113
x=4 , 1\frac{1}{3}
Decimal form: x=4,1.333
x=4 , 1.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
4|x2|=|2x|
without the absolute value bars:

|x|=|y|4|x2|=|2x|
x=+y4(x2)=(2x)
x=y4(x2)=(2x)
+x=y4(x2)=(2x)
x=y4((x2))=(2x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|4|x2|=|2x|
x=+y , +x=y4(x2)=(2x)
x=y , x=y4(x2)=(2x)

2. Solve the two equations for x

12 additional steps

4·(x-2)=2x

Expand the parentheses:

4x+4·-2=2x

Simplify the arithmetic:

4x8=2x

Subtract from both sides:

(4x-8)-2x=(2x)-2x

Group like terms:

(4x-2x)-8=(2x)-2x

Simplify the arithmetic:

2x-8=(2x)-2x

Simplify the arithmetic:

2x8=0

Add to both sides:

(2x-8)+8=0+8

Simplify the arithmetic:

2x=0+8

Simplify the arithmetic:

2x=8

Divide both sides by :

(2x)2=82

Simplify the fraction:

x=82

Find the greatest common factor of the numerator and denominator:

x=(4·2)(1·2)

Factor out and cancel the greatest common factor:

x=4

12 additional steps

4·(x-2)=-(2x)

Expand the parentheses:

4x+4·-2=-(2x)

Simplify the arithmetic:

4x-8=-(2x)

Add to both sides:

(4x-8)+2x=(-2x)+2x

Group like terms:

(4x+2x)-8=(-2x)+2x

Simplify the arithmetic:

6x-8=(-2x)+2x

Simplify the arithmetic:

6x8=0

Add to both sides:

(6x-8)+8=0+8

Simplify the arithmetic:

6x=0+8

Simplify the arithmetic:

6x=8

Divide both sides by :

(6x)6=86

Simplify the fraction:

x=86

Find the greatest common factor of the numerator and denominator:

x=(4·2)(3·2)

Factor out and cancel the greatest common factor:

x=43

3. List the solutions

x=4,43
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=4|x2|
y=|2x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.