Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=152,16
x=\frac{15}{2} , \frac{1}{6}
Mixed number form: x=712,16
x=7\frac{1}{2} , \frac{1}{6}
Decimal form: x=7.5,0.167
x=7.5 , 0.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
4|x2|=|2x+7|
without the absolute value bars:

|x|=|y|4|x2|=|2x+7|
x=+y4(x2)=(2x+7)
x=y4(x2)=(2x+7)
+x=y4(x2)=(2x+7)
x=y4((x2))=(2x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|4|x2|=|2x+7|
x=+y , +x=y4(x2)=(2x+7)
x=y , x=y4(x2)=(2x+7)

2. Solve the two equations for x

11 additional steps

4·(x-2)=(2x+7)

Expand the parentheses:

4x+4·-2=(2x+7)

Simplify the arithmetic:

4x-8=(2x+7)

Subtract from both sides:

(4x-8)-2x=(2x+7)-2x

Group like terms:

(4x-2x)-8=(2x+7)-2x

Simplify the arithmetic:

2x-8=(2x+7)-2x

Group like terms:

2x-8=(2x-2x)+7

Simplify the arithmetic:

2x8=7

Add to both sides:

(2x-8)+8=7+8

Simplify the arithmetic:

2x=7+8

Simplify the arithmetic:

2x=15

Divide both sides by :

(2x)2=152

Simplify the fraction:

x=152

12 additional steps

4·(x-2)=-(2x+7)

Expand the parentheses:

4x+4·-2=-(2x+7)

Simplify the arithmetic:

4x-8=-(2x+7)

Expand the parentheses:

4x8=2x7

Add to both sides:

(4x-8)+2x=(-2x-7)+2x

Group like terms:

(4x+2x)-8=(-2x-7)+2x

Simplify the arithmetic:

6x-8=(-2x-7)+2x

Group like terms:

6x-8=(-2x+2x)-7

Simplify the arithmetic:

6x8=7

Add to both sides:

(6x-8)+8=-7+8

Simplify the arithmetic:

6x=7+8

Simplify the arithmetic:

6x=1

Divide both sides by :

(6x)6=16

Simplify the fraction:

x=16

3. List the solutions

x=152,16
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=4|x2|
y=|2x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.