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Solution - Absolute value equations

Exact form: a=10,23
a=10 , \frac{2}{3}
Decimal form: a=10,0.667
a=10 , 0.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
4|a3|=|2a+8|
without the absolute value bars:

|x|=|y|4|a3|=|2a+8|
x=+y4(a3)=(2a+8)
x=y4(a3)=(2a+8)
+x=y4(a3)=(2a+8)
x=y4((a3))=(2a+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|4|a3|=|2a+8|
x=+y , +x=y4(a3)=(2a+8)
x=y , x=y4(a3)=(2a+8)

2. Solve the two equations for a

13 additional steps

4·(a-3)=(2a+8)

Expand the parentheses:

4a+4·-3=(2a+8)

Simplify the arithmetic:

4a-12=(2a+8)

Subtract from both sides:

(4a-12)-2a=(2a+8)-2a

Group like terms:

(4a-2a)-12=(2a+8)-2a

Simplify the arithmetic:

2a-12=(2a+8)-2a

Group like terms:

2a-12=(2a-2a)+8

Simplify the arithmetic:

2a12=8

Add to both sides:

(2a-12)+12=8+12

Simplify the arithmetic:

2a=8+12

Simplify the arithmetic:

2a=20

Divide both sides by :

(2a)2=202

Simplify the fraction:

a=202

Find the greatest common factor of the numerator and denominator:

a=(10·2)(1·2)

Factor out and cancel the greatest common factor:

a=10

14 additional steps

4·(a-3)=-(2a+8)

Expand the parentheses:

4a+4·-3=-(2a+8)

Simplify the arithmetic:

4a-12=-(2a+8)

Expand the parentheses:

4a12=2a8

Add to both sides:

(4a-12)+2a=(-2a-8)+2a

Group like terms:

(4a+2a)-12=(-2a-8)+2a

Simplify the arithmetic:

6a-12=(-2a-8)+2a

Group like terms:

6a-12=(-2a+2a)-8

Simplify the arithmetic:

6a12=8

Add to both sides:

(6a-12)+12=-8+12

Simplify the arithmetic:

6a=8+12

Simplify the arithmetic:

6a=4

Divide both sides by :

(6a)6=46

Simplify the fraction:

a=46

Find the greatest common factor of the numerator and denominator:

a=(2·2)(3·2)

Factor out and cancel the greatest common factor:

a=23

3. List the solutions

a=10,23
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=4|a3|
y=|2a+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.