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Solution - Absolute value equations

Exact form: x=7,52
x=7 , \frac{5}{2}
Mixed number form: x=7,212
x=7 , 2\frac{1}{2}
Decimal form: x=7,2.5
x=7 , 2.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
3|x4|=|x+2|
without the absolute value bars:

|x|=|y|3|x4|=|x+2|
x=+y3(x4)=(x+2)
x=y3(x4)=(x+2)
+x=y3(x4)=(x+2)
x=y3((x4))=(x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|3|x4|=|x+2|
x=+y , +x=y3(x4)=(x+2)
x=y , x=y3(x4)=(x+2)

2. Solve the two equations for x

13 additional steps

3·(x-4)=(x+2)

Expand the parentheses:

3x+3·-4=(x+2)

Simplify the arithmetic:

3x-12=(x+2)

Subtract from both sides:

(3x-12)-x=(x+2)-x

Group like terms:

(3x-x)-12=(x+2)-x

Simplify the arithmetic:

2x-12=(x+2)-x

Group like terms:

2x-12=(x-x)+2

Simplify the arithmetic:

2x12=2

Add to both sides:

(2x-12)+12=2+12

Simplify the arithmetic:

2x=2+12

Simplify the arithmetic:

2x=14

Divide both sides by :

(2x)2=142

Simplify the fraction:

x=142

Find the greatest common factor of the numerator and denominator:

x=(7·2)(1·2)

Factor out and cancel the greatest common factor:

x=7

14 additional steps

3·(x-4)=-(x+2)

Expand the parentheses:

3x+3·-4=-(x+2)

Simplify the arithmetic:

3x-12=-(x+2)

Expand the parentheses:

3x12=x2

Add to both sides:

(3x-12)+x=(-x-2)+x

Group like terms:

(3x+x)-12=(-x-2)+x

Simplify the arithmetic:

4x-12=(-x-2)+x

Group like terms:

4x-12=(-x+x)-2

Simplify the arithmetic:

4x12=2

Add to both sides:

(4x-12)+12=-2+12

Simplify the arithmetic:

4x=2+12

Simplify the arithmetic:

4x=10

Divide both sides by :

(4x)4=104

Simplify the fraction:

x=104

Find the greatest common factor of the numerator and denominator:

x=(5·2)(2·2)

Factor out and cancel the greatest common factor:

x=52

3. List the solutions

x=7,52
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=3|x4|
y=|x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.