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Solution - Absolute value equations

Exact form: x=12,125
x=12 , \frac{12}{5}
Mixed number form: x=12,225
x=12 , 2\frac{2}{5}
Decimal form: x=12,2.4
x=12 , 2.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
3|x4|=|2x|
without the absolute value bars:

|x|=|y|3|x4|=|2x|
x=+y3(x4)=(2x)
x=y3(x4)=(2x)
+x=y3(x4)=(2x)
x=y3((x4))=(2x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|3|x4|=|2x|
x=+y , +x=y3(x4)=(2x)
x=y , x=y3(x4)=(2x)

2. Solve the two equations for x

8 additional steps

3·(x-4)=2x

Expand the parentheses:

3x+3·-4=2x

Simplify the arithmetic:

3x12=2x

Subtract from both sides:

(3x-12)-2x=(2x)-2x

Group like terms:

(3x-2x)-12=(2x)-2x

Simplify the arithmetic:

x-12=(2x)-2x

Simplify the arithmetic:

x12=0

Add to both sides:

(x-12)+12=0+12

Simplify the arithmetic:

x=0+12

Simplify the arithmetic:

x=12

10 additional steps

3·(x-4)=-(2x)

Expand the parentheses:

3x+3·-4=-(2x)

Simplify the arithmetic:

3x-12=-(2x)

Add to both sides:

(3x-12)+2x=(-2x)+2x

Group like terms:

(3x+2x)-12=(-2x)+2x

Simplify the arithmetic:

5x-12=(-2x)+2x

Simplify the arithmetic:

5x12=0

Add to both sides:

(5x-12)+12=0+12

Simplify the arithmetic:

5x=0+12

Simplify the arithmetic:

5x=12

Divide both sides by :

(5x)5=125

Simplify the fraction:

x=125

3. List the solutions

x=12,125
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=3|x4|
y=|2x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.