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Solution - Absolute value equations

Exact form: x=112,-54
x=\frac{11}{2} , -\frac{5}{4}
Mixed number form: x=512,-114
x=5\frac{1}{2} , -1\frac{1}{4}
Decimal form: x=5.5,1.25
x=5.5 , -1.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
3|x1|=|x+8|
without the absolute value bars:

|x|=|y|3|x1|=|x+8|
x=+y3(x1)=(x+8)
x=y3(x1)=(x+8)
+x=y3(x1)=(x+8)
x=y3((x1))=(x+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|3|x1|=|x+8|
x=+y , +x=y3(x1)=(x+8)
x=y , x=y3(x1)=(x+8)

2. Solve the two equations for x

11 additional steps

3·(x-1)=(x+8)

Expand the parentheses:

3x+3·-1=(x+8)

Simplify the arithmetic:

3x-3=(x+8)

Subtract from both sides:

(3x-3)-x=(x+8)-x

Group like terms:

(3x-x)-3=(x+8)-x

Simplify the arithmetic:

2x-3=(x+8)-x

Group like terms:

2x-3=(x-x)+8

Simplify the arithmetic:

2x3=8

Add to both sides:

(2x-3)+3=8+3

Simplify the arithmetic:

2x=8+3

Simplify the arithmetic:

2x=11

Divide both sides by :

(2x)2=112

Simplify the fraction:

x=112

12 additional steps

3·(x-1)=-(x+8)

Expand the parentheses:

3x+3·-1=-(x+8)

Simplify the arithmetic:

3x-3=-(x+8)

Expand the parentheses:

3x3=x8

Add to both sides:

(3x-3)+x=(-x-8)+x

Group like terms:

(3x+x)-3=(-x-8)+x

Simplify the arithmetic:

4x-3=(-x-8)+x

Group like terms:

4x-3=(-x+x)-8

Simplify the arithmetic:

4x3=8

Add to both sides:

(4x-3)+3=-8+3

Simplify the arithmetic:

4x=8+3

Simplify the arithmetic:

4x=5

Divide both sides by :

(4x)4=-54

Simplify the fraction:

x=-54

3. List the solutions

x=112,-54
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=3|x1|
y=|x+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.