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Solution - Absolute value equations

Exact form: x=11,1
x=11 , -1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
3|x1|=|2x+8|
without the absolute value bars:

|x|=|y|3|x1|=|2x+8|
x=+y3(x1)=(2x+8)
x=y3(x1)=(2x+8)
+x=y3(x1)=(2x+8)
x=y3((x1))=(2x+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|3|x1|=|2x+8|
x=+y , +x=y3(x1)=(2x+8)
x=y , x=y3(x1)=(2x+8)

2. Solve the two equations for x

9 additional steps

3·(x-1)=(2x+8)

Expand the parentheses:

3x+3·-1=(2x+8)

Simplify the arithmetic:

3x-3=(2x+8)

Subtract from both sides:

(3x-3)-2x=(2x+8)-2x

Group like terms:

(3x-2x)-3=(2x+8)-2x

Simplify the arithmetic:

x-3=(2x+8)-2x

Group like terms:

x-3=(2x-2x)+8

Simplify the arithmetic:

x3=8

Add to both sides:

(x-3)+3=8+3

Simplify the arithmetic:

x=8+3

Simplify the arithmetic:

x=11

13 additional steps

3·(x-1)=-(2x+8)

Expand the parentheses:

3x+3·-1=-(2x+8)

Simplify the arithmetic:

3x-3=-(2x+8)

Expand the parentheses:

3x3=2x8

Add to both sides:

(3x-3)+2x=(-2x-8)+2x

Group like terms:

(3x+2x)-3=(-2x-8)+2x

Simplify the arithmetic:

5x-3=(-2x-8)+2x

Group like terms:

5x-3=(-2x+2x)-8

Simplify the arithmetic:

5x3=8

Add to both sides:

(5x-3)+3=-8+3

Simplify the arithmetic:

5x=8+3

Simplify the arithmetic:

5x=5

Divide both sides by :

(5x)5=-55

Simplify the fraction:

x=-55

Simplify the fraction:

x=1

3. List the solutions

x=11,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=3|x1|
y=|2x+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.