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Solution - Absolute value equations

Exact form:

x = - \frac{21}{2}, - \frac{33}{4}

x=-\frac{21}{2} , -\frac{33}{4}

Mixed number form:

x = - 10 \frac{1}{2}, - 8 \frac{1}{4}

x=-10\frac{1}{2} , -8\frac{1}{4}

Decimal form:

x = - 10.5, - 8.25

x=-10.5 , -8.25

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$3 | x + 9 | = | x + 6 |$
without the absolute value bars:

$\| x \| = \| y \|$	$3 \| x + 9 \| = \| x + 6 \|$
$x = + y$	$3 (x + 9) = (x + 6)$
$x = - y$	$3 (x + 9) = - (x + 6)$
$+ x = y$	$3 (x + 9) = (x + 6)$
$- x = y$	$3 (- (x + 9)) = (x + 6)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$3 \| x + 9 \| = \| x + 6 \|$
$x = + y$ , $+ x = y$	$3 (x + 9) = (x + 6)$
$x = - y$ , $- x = y$	$3 (x + 9) = - (x + 6)$

2. Solve the two equations for x

11 additional steps

$3 \cdot (x + 9) = (x + 6)$

Expand the parentheses:

$3 x + 3 \cdot 9 = (x + 6)$

Simplify the arithmetic:

$3 x + 27 = (x + 6)$

Subtract from both sides:

$(3 x + 27) - x = (x + 6) - x$

Group like terms:

$(3 x - x) + 27 = (x + 6) - x$

Simplify the arithmetic:

$2 x + 27 = (x + 6) - x$

Group like terms:

$2 x + 27 = (x - x) + 6$

Simplify the arithmetic:

$2 x + 27 = 6$

Subtract from both sides:

$(2 x + 27) - 27 = 6 - 27$

Simplify the arithmetic:

$2 x = 6 - 27$

Simplify the arithmetic:

$2 x = - 21$

Divide both sides by :

$\frac{(2 x)}{2} = \frac{- 21}{2}$

Simplify the fraction:

$x = \frac{- 21}{2}$

12 additional steps

$3 \cdot (x + 9) = - (x + 6)$

Expand the parentheses:

$3 x + 3 \cdot 9 = - (x + 6)$

Simplify the arithmetic:

$3 x + 27 = - (x + 6)$

Expand the parentheses:

$3 x + 27 = - x - 6$

Add to both sides:

$(3 x + 27) + x = (- x - 6) + x$

Group like terms:

$(3 x + x) + 27 = (- x - 6) + x$

Simplify the arithmetic:

$4 x + 27 = (- x - 6) + x$

Group like terms:

$4 x + 27 = (- x + x) - 6$

Simplify the arithmetic:

$4 x + 27 = - 6$

Subtract from both sides:

$(4 x + 27) - 27 = - 6 - 27$

Simplify the arithmetic:

$4 x = - 6 - 27$

Simplify the arithmetic:

$4 x = - 33$

Divide both sides by :

$\frac{(4 x)}{4} = \frac{- 33}{4}$

Simplify the fraction:

$x = \frac{- 33}{4}$

3. List the solutions

$x = - \frac{21}{2}, - \frac{33}{4}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = 3 | x + 9 |$
$y = | x + 6 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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