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Solution - Absolute value equations

Exact form: x=716,-12
x=\frac{7}{16} , -\frac{1}{2}
Decimal form: x=0.438,0.5
x=0.438 , -0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
3|3x1|=|7x+4|
without the absolute value bars:

|x|=|y|3|3x1|=|7x+4|
x=+y3(3x1)=(7x+4)
x=y3(3x1)=(7x+4)
+x=y3(3x1)=(7x+4)
x=y3((3x1))=(7x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|3|3x1|=|7x+4|
x=+y , +x=y3(3x1)=(7x+4)
x=y , x=y3(3x1)=(7x+4)

2. Solve the two equations for x

12 additional steps

3·(3x-1)=(-7x+4)

Expand the parentheses:

3·3x+3·-1=(-7x+4)

Multiply the coefficients:

9x+3·-1=(-7x+4)

Simplify the arithmetic:

9x-3=(-7x+4)

Add to both sides:

(9x-3)+7x=(-7x+4)+7x

Group like terms:

(9x+7x)-3=(-7x+4)+7x

Simplify the arithmetic:

16x-3=(-7x+4)+7x

Group like terms:

16x-3=(-7x+7x)+4

Simplify the arithmetic:

16x3=4

Add to both sides:

(16x-3)+3=4+3

Simplify the arithmetic:

16x=4+3

Simplify the arithmetic:

16x=7

Divide both sides by :

(16x)16=716

Simplify the fraction:

x=716

13 additional steps

3·(3x-1)=-(-7x+4)

Expand the parentheses:

3·3x+3·-1=-(-7x+4)

Multiply the coefficients:

9x+3·-1=-(-7x+4)

Simplify the arithmetic:

9x-3=-(-7x+4)

Expand the parentheses:

9x3=7x4

Subtract from both sides:

(9x-3)-7x=(7x-4)-7x

Group like terms:

(9x-7x)-3=(7x-4)-7x

Simplify the arithmetic:

2x-3=(7x-4)-7x

Group like terms:

2x-3=(7x-7x)-4

Simplify the arithmetic:

2x3=4

Add to both sides:

(2x-3)+3=-4+3

Simplify the arithmetic:

2x=4+3

Simplify the arithmetic:

2x=1

Divide both sides by :

(2x)2=-12

Simplify the fraction:

x=-12

3. List the solutions

x=716,-12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=3|3x1|
y=|7x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.