Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-2,47
x=-2 , \frac{4}{7}
Decimal form: x=2,0.571
x=-2 , 0.571

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
3|2x+1|=|x7|
without the absolute value bars:

|x|=|y|3|2x+1|=|x7|
x=+y3(2x+1)=(x7)
x=y3(2x+1)=(x7)
+x=y3(2x+1)=(x7)
x=y3((2x+1))=(x7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|3|2x+1|=|x7|
x=+y , +x=y3(2x+1)=(x7)
x=y , x=y3(2x+1)=(x7)

2. Solve the two equations for x

14 additional steps

3·(2x+1)=(x-7)

Expand the parentheses:

3·2x+3·1=(x-7)

Multiply the coefficients:

6x+3·1=(x-7)

Simplify the arithmetic:

6x+3=(x-7)

Subtract from both sides:

(6x+3)-x=(x-7)-x

Group like terms:

(6x-x)+3=(x-7)-x

Simplify the arithmetic:

5x+3=(x-7)-x

Group like terms:

5x+3=(x-x)-7

Simplify the arithmetic:

5x+3=7

Subtract from both sides:

(5x+3)-3=-7-3

Simplify the arithmetic:

5x=73

Simplify the arithmetic:

5x=10

Divide both sides by :

(5x)5=-105

Simplify the fraction:

x=-105

Find the greatest common factor of the numerator and denominator:

x=(-2·5)(1·5)

Factor out and cancel the greatest common factor:

x=2

13 additional steps

3·(2x+1)=-(x-7)

Expand the parentheses:

3·2x+3·1=-(x-7)

Multiply the coefficients:

6x+3·1=-(x-7)

Simplify the arithmetic:

6x+3=-(x-7)

Expand the parentheses:

6x+3=x+7

Add to both sides:

(6x+3)+x=(-x+7)+x

Group like terms:

(6x+x)+3=(-x+7)+x

Simplify the arithmetic:

7x+3=(-x+7)+x

Group like terms:

7x+3=(-x+x)+7

Simplify the arithmetic:

7x+3=7

Subtract from both sides:

(7x+3)-3=7-3

Simplify the arithmetic:

7x=73

Simplify the arithmetic:

7x=4

Divide both sides by :

(7x)7=47

Simplify the fraction:

x=47

3. List the solutions

x=-2,47
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=3|2x+1|
y=|x7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.