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Solution - Absolute value equations

Exact form: x=-1,13
x=-1 , \frac{1}{3}
Decimal form: x=1,0.333
x=-1 , 0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|x1|=4|x|
without the absolute value bars:

|x|=|y|2|x1|=4|x|
x=+y2(x1)=4(x)
x=y2(x1)=4((x))
+x=y2(x1)=4(x)
x=y2((x1))=4(x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|x1|=4|x|
x=+y , +x=y2(x1)=4(x)
x=y , x=y2(x1)=4((x))

2. Solve the two equations for x

13 additional steps

2·(x-1)=4x

Expand the parentheses:

2x+2·-1=4x

Simplify the arithmetic:

2x2=4x

Subtract from both sides:

(2x-2)-4x=(4x)-4x

Group like terms:

(2x-4x)-2=(4x)-4x

Simplify the arithmetic:

-2x-2=(4x)-4x

Simplify the arithmetic:

2x2=0

Add to both sides:

(-2x-2)+2=0+2

Simplify the arithmetic:

2x=0+2

Simplify the arithmetic:

2x=2

Divide both sides by :

(-2x)-2=2-2

Cancel out the negatives:

2x2=2-2

Simplify the fraction:

x=2-2

Move the negative sign from the denominator to the numerator:

x=-22

Simplify the fraction:

x=1

14 additional steps

2·(x-1)=4·-x

Expand the parentheses:

2x+2·-1=4·-x

Simplify the arithmetic:

2x-2=4·-x

Group like terms:

2x-2=(4·-1)x

Multiply the coefficients:

2x2=4x

Add to both sides:

(2x-2)+4x=(-4x)+4x

Group like terms:

(2x+4x)-2=(-4x)+4x

Simplify the arithmetic:

6x-2=(-4x)+4x

Simplify the arithmetic:

6x2=0

Add to both sides:

(6x-2)+2=0+2

Simplify the arithmetic:

6x=0+2

Simplify the arithmetic:

6x=2

Divide both sides by :

(6x)6=26

Simplify the fraction:

x=26

Find the greatest common factor of the numerator and denominator:

x=(1·2)(3·2)

Factor out and cancel the greatest common factor:

x=13

3. List the solutions

x=-1,13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=2|x1|
y=4|x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.