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Solution - Absolute value equations

Exact form: x=43,0
x=\frac{4}{3} , 0
Mixed number form: x=113,0
x=1\frac{1}{3} , 0
Decimal form: x=1.333,0
x=1.333 , 0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|x1|=|x+2|
without the absolute value bars:

|x|=|y|2|x1|=|x+2|
x=+y2(x1)=(x+2)
x=y2(x1)=(x+2)
+x=y2(x1)=(x+2)
x=y2((x1))=(x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|x1|=|x+2|
x=+y , +x=y2(x1)=(x+2)
x=y , x=y2(x1)=(x+2)

2. Solve the two equations for x

11 additional steps

2·(x-1)=(-x+2)

Expand the parentheses:

2x+2·-1=(-x+2)

Simplify the arithmetic:

2x-2=(-x+2)

Add to both sides:

(2x-2)+x=(-x+2)+x

Group like terms:

(2x+x)-2=(-x+2)+x

Simplify the arithmetic:

3x-2=(-x+2)+x

Group like terms:

3x-2=(-x+x)+2

Simplify the arithmetic:

3x2=2

Add to both sides:

(3x-2)+2=2+2

Simplify the arithmetic:

3x=2+2

Simplify the arithmetic:

3x=4

Divide both sides by :

(3x)3=43

Simplify the fraction:

x=43

10 additional steps

2·(x-1)=-(-x+2)

Expand the parentheses:

2x+2·-1=-(-x+2)

Simplify the arithmetic:

2x-2=-(-x+2)

Expand the parentheses:

2x2=x2

Subtract from both sides:

(2x-2)-x=(x-2)-x

Group like terms:

(2x-x)-2=(x-2)-x

Simplify the arithmetic:

x-2=(x-2)-x

Group like terms:

x-2=(x-x)-2

Simplify the arithmetic:

x2=2

Add to both sides:

(x-2)+2=-2+2

Simplify the arithmetic:

x=2+2

Simplify the arithmetic:

x=0

3. List the solutions

x=43,0
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=2|x1|
y=|x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.