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Solution - Absolute value equations

Exact form: x=1,15
x=1 , \frac{1}{5}
Decimal form: x=1,0.2
x=1 , 0.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2|x|+|3x+1|=0

Add |3x+1| to both sides of the equation:

2|x|+|3x+1||3x+1|=|3x+1|

Simplify the arithmetic

2|x|=|3x+1|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|x|=|3x+1|
without the absolute value bars:

|x|=|y|2|x|=|3x+1|
x=+y2(x)=(3x+1)
x=y2(x)=(3x+1)
+x=y2(x)=(3x+1)
x=y2((x))=(3x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|x|=|3x+1|
x=+y , +x=y2(x)=(3x+1)
x=y , x=y2(x)=(3x+1)

3. Solve the two equations for x

7 additional steps

2x=-(-3x+1)

Expand the parentheses:

2x=3x1

Subtract from both sides:

(2x)-3x=(3x-1)-3x

Simplify the arithmetic:

-x=(3x-1)-3x

Group like terms:

-x=(3x-3x)-1

Simplify the arithmetic:

x=1

Multiply both sides by :

-x·-1=-1·-1

Remove the one(s):

x=-1·-1

Simplify the arithmetic:

x=1

6 additional steps

2x=-(-(-3x+1))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

2x=3x+1

Add to both sides:

(2x)+3x=(-3x+1)+3x

Simplify the arithmetic:

5x=(-3x+1)+3x

Group like terms:

5x=(-3x+3x)+1

Simplify the arithmetic:

5x=1

Divide both sides by :

(5x)5=15

Simplify the fraction:

x=15

4. List the solutions

x=1,15
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=2|x|
y=|3x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.