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Solution - Absolute value equations

Exact form: x=12,-85
x=12 , -\frac{8}{5}
Mixed number form: x=12,-135
x=12 , -1\frac{3}{5}
Decimal form: x=12,1.6
x=12 , -1.6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|x+5|=|3x2|
without the absolute value bars:

|x|=|y|2|x+5|=|3x2|
x=+y2(x+5)=(3x2)
x=y2(x+5)=(3x2)
+x=y2(x+5)=(3x2)
x=y2((x+5))=(3x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|x+5|=|3x2|
x=+y , +x=y2(x+5)=(3x2)
x=y , x=y2(x+5)=(3x2)

2. Solve the two equations for x

12 additional steps

2·(x+5)=(3x-2)

Expand the parentheses:

2x+2·5=(3x-2)

Simplify the arithmetic:

2x+10=(3x-2)

Subtract from both sides:

(2x+10)-3x=(3x-2)-3x

Group like terms:

(2x-3x)+10=(3x-2)-3x

Simplify the arithmetic:

-x+10=(3x-2)-3x

Group like terms:

-x+10=(3x-3x)-2

Simplify the arithmetic:

x+10=2

Subtract from both sides:

(-x+10)-10=-2-10

Simplify the arithmetic:

x=210

Simplify the arithmetic:

x=12

Multiply both sides by :

-x·-1=-12·-1

Remove the one(s):

x=-12·-1

Simplify the arithmetic:

x=12

12 additional steps

2·(x+5)=-(3x-2)

Expand the parentheses:

2x+2·5=-(3x-2)

Simplify the arithmetic:

2x+10=-(3x-2)

Expand the parentheses:

2x+10=3x+2

Add to both sides:

(2x+10)+3x=(-3x+2)+3x

Group like terms:

(2x+3x)+10=(-3x+2)+3x

Simplify the arithmetic:

5x+10=(-3x+2)+3x

Group like terms:

5x+10=(-3x+3x)+2

Simplify the arithmetic:

5x+10=2

Subtract from both sides:

(5x+10)-10=2-10

Simplify the arithmetic:

5x=210

Simplify the arithmetic:

5x=8

Divide both sides by :

(5x)5=-85

Simplify the fraction:

x=-85

3. List the solutions

x=12,-85
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=2|x+5|
y=|3x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.