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Solution - Absolute value equations

Exact form: x=-11,-13
x=-11 , -\frac{1}{3}
Decimal form: x=11,0.333
x=-11 , -0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2|x+3||x5|=0

Add |x5| to both sides of the equation:

2|x+3||x5|+|x5|=|x5|

Simplify the arithmetic

2|x+3|=|x5|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|x+3|=|x5|
without the absolute value bars:

|x|=|y|2|x+3|=|x5|
x=+y2(x+3)=(x5)
x=y2(x+3)=((x5))
+x=y2(x+3)=(x5)
x=y2((x+3))=(x5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|x+3|=|x5|
x=+y , +x=y2(x+3)=(x5)
x=y , x=y2(x+3)=((x5))

3. Solve the two equations for x

9 additional steps

2·(x+3)=(x-5)

Expand the parentheses:

2x+2·3=(x-5)

Simplify the arithmetic:

2x+6=(x-5)

Subtract from both sides:

(2x+6)-x=(x-5)-x

Group like terms:

(2x-x)+6=(x-5)-x

Simplify the arithmetic:

x+6=(x-5)-x

Group like terms:

x+6=(x-x)-5

Simplify the arithmetic:

x+6=5

Subtract from both sides:

(x+6)-6=-5-6

Simplify the arithmetic:

x=56

Simplify the arithmetic:

x=11

12 additional steps

2·(x+3)=(-(x-5))

Expand the parentheses:

2x+2·3=(-(x-5))

Simplify the arithmetic:

2x+6=(-(x-5))

Expand the parentheses:

2x+6=x+5

Add to both sides:

(2x+6)+x=(-x+5)+x

Group like terms:

(2x+x)+6=(-x+5)+x

Simplify the arithmetic:

3x+6=(-x+5)+x

Group like terms:

3x+6=(-x+x)+5

Simplify the arithmetic:

3x+6=5

Subtract from both sides:

(3x+6)-6=5-6

Simplify the arithmetic:

3x=56

Simplify the arithmetic:

3x=1

Divide both sides by :

(3x)3=-13

Simplify the fraction:

x=-13

4. List the solutions

x=-11,-13
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=2|x+3|
y=|x5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.