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Solution - Absolute value equations

Exact form:

x = - 9, - \frac{21}{5}

x=-9 , -\frac{21}{5}

Mixed number form:

x = - 9, - 4 \frac{1}{5}

x=-9 , -4\frac{1}{5}

Decimal form:

x = - 9, - 4.2

x=-9 , -4.2

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$2 | x + 3 | = 3 | x + 5 |$
without the absolute value bars:

$\| x \| = \| y \|$	$2 \| x + 3 \| = 3 \| x + 5 \|$
$x = + y$	$2 (x + 3) = 3 (x + 5)$
$x = - y$	$2 (x + 3) = 3 (- (x + 5))$
$+ x = y$	$2 (x + 3) = 3 (x + 5)$
$- x = y$	$2 (- (x + 3)) = 3 (x + 5)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$2 \| x + 3 \| = 3 \| x + 5 \|$
$x = + y$ , $+ x = y$	$2 (x + 3) = 3 (x + 5)$
$x = - y$ , $- x = y$	$2 (x + 3) = 3 (- (x + 5))$

2. Solve the two equations for x

14 additional steps

$2 \cdot (x + 3) = 3 \cdot (x + 5)$

Expand the parentheses:

$2 x + 2 \cdot 3 = 3 \cdot (x + 5)$

Simplify the arithmetic:

$2 x + 6 = 3 \cdot (x + 5)$

Expand the parentheses:

$2 x + 6 = 3 x + 3 \cdot 5$

Simplify the arithmetic:

$2 x + 6 = 3 x + 15$

Subtract from both sides:

$(2 x + 6) - 3 x = (3 x + 15) - 3 x$

Group like terms:

$(2 x - 3 x) + 6 = (3 x + 15) - 3 x$

Simplify the arithmetic:

$- x + 6 = (3 x + 15) - 3 x$

Group like terms:

$- x + 6 = (3 x - 3 x) + 15$

Simplify the arithmetic:

$- x + 6 = 15$

Subtract from both sides:

$(- x + 6) - 6 = 15 - 6$

Simplify the arithmetic:

$- x = 15 - 6$

Simplify the arithmetic:

$- x = 9$

Multiply both sides by :

$- x \cdot - 1 = 9 \cdot - 1$

Remove the one(s):

$x = 9 \cdot - 1$

Simplify the arithmetic:

$x = - 9$

16 additional steps

$2 \cdot (x + 3) = 3 \cdot (- (x + 5))$

Expand the parentheses:

$2 x + 2 \cdot 3 = 3 \cdot (- (x + 5))$

Simplify the arithmetic:

$2 x + 6 = 3 \cdot (- (x + 5))$

Expand the parentheses:

$2 x + 6 = 3 \cdot (- x - 5)$

$2 x + 6 = 3 \cdot - x + 3 \cdot - 5$

Group like terms:

$2 x + 6 = (3 \cdot - 1) x + 3 \cdot - 5$

Multiply the coefficients:

$2 x + 6 = - 3 x + 3 \cdot - 5$

Simplify the arithmetic:

$2 x + 6 = - 3 x - 15$

Add to both sides:

$(2 x + 6) + 3 x = (- 3 x - 15) + 3 x$

Group like terms:

$(2 x + 3 x) + 6 = (- 3 x - 15) + 3 x$

Simplify the arithmetic:

$5 x + 6 = (- 3 x - 15) + 3 x$

Group like terms:

$5 x + 6 = (- 3 x + 3 x) - 15$

Simplify the arithmetic:

$5 x + 6 = - 15$

Subtract from both sides:

$(5 x + 6) - 6 = - 15 - 6$

Simplify the arithmetic:

$5 x = - 15 - 6$

Simplify the arithmetic:

$5 x = - 21$

Divide both sides by :

$\frac{(5 x)}{5} = \frac{- 21}{5}$

Simplify the fraction:

$x = \frac{- 21}{5}$

3. List the solutions

$x = - 9, - \frac{21}{5}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = 2 | x + 3 |$
$y = 3 | x + 5 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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