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Solution - Absolute value equations

Exact form: x=3,3
x=-3 , -3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|x+3|=|x+3|
without the absolute value bars:

|x|=|y|2|x+3|=|x+3|
x=+y2(x+3)=(x+3)
x=y2(x+3)=(x+3)
+x=y2(x+3)=(x+3)
x=y2((x+3))=(x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|x+3|=|x+3|
x=+y , +x=y2(x+3)=(x+3)
x=y , x=y2(x+3)=(x+3)

2. Solve the two equations for x

9 additional steps

2·(x+3)=(x+3)

Expand the parentheses:

2x+2·3=(x+3)

Simplify the arithmetic:

2x+6=(x+3)

Subtract from both sides:

(2x+6)-x=(x+3)-x

Group like terms:

(2x-x)+6=(x+3)-x

Simplify the arithmetic:

x+6=(x+3)-x

Group like terms:

x+6=(x-x)+3

Simplify the arithmetic:

x+6=3

Subtract from both sides:

(x+6)-6=3-6

Simplify the arithmetic:

x=36

Simplify the arithmetic:

x=3

14 additional steps

2·(x+3)=-(x+3)

Expand the parentheses:

2x+2·3=-(x+3)

Simplify the arithmetic:

2x+6=-(x+3)

Expand the parentheses:

2x+6=x3

Add to both sides:

(2x+6)+x=(-x-3)+x

Group like terms:

(2x+x)+6=(-x-3)+x

Simplify the arithmetic:

3x+6=(-x-3)+x

Group like terms:

3x+6=(-x+x)-3

Simplify the arithmetic:

3x+6=3

Subtract from both sides:

(3x+6)-6=-3-6

Simplify the arithmetic:

3x=36

Simplify the arithmetic:

3x=9

Divide both sides by :

(3x)3=-93

Simplify the fraction:

x=-93

Find the greatest common factor of the numerator and denominator:

x=(-3·3)(1·3)

Factor out and cancel the greatest common factor:

x=3

3. List the solutions

x=3,3
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=2|x+3|
y=|x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.