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Solution - Absolute value equations

Exact form: x=0,-43
x=0 , -\frac{4}{3}
Mixed number form: x=0,-113
x=0 , -1\frac{1}{3}
Decimal form: x=0,1.333
x=0 , -1.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|x+1|=|x+2|
without the absolute value bars:

|x|=|y|2|x+1|=|x+2|
x=+y2(x+1)=(x+2)
x=y2(x+1)=(x+2)
+x=y2(x+1)=(x+2)
x=y2((x+1))=(x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|x+1|=|x+2|
x=+y , +x=y2(x+1)=(x+2)
x=y , x=y2(x+1)=(x+2)

2. Solve the two equations for x

9 additional steps

2·(x+1)=(x+2)

Expand the parentheses:

2x+2·1=(x+2)

Simplify the arithmetic:

2x+2=(x+2)

Subtract from both sides:

(2x+2)-x=(x+2)-x

Group like terms:

(2x-x)+2=(x+2)-x

Simplify the arithmetic:

x+2=(x+2)-x

Group like terms:

x+2=(x-x)+2

Simplify the arithmetic:

x+2=2

Subtract from both sides:

(x+2)-2=2-2

Simplify the arithmetic:

x=22

Simplify the arithmetic:

x=0

12 additional steps

2·(x+1)=-(x+2)

Expand the parentheses:

2x+2·1=-(x+2)

Simplify the arithmetic:

2x+2=-(x+2)

Expand the parentheses:

2x+2=x2

Add to both sides:

(2x+2)+x=(-x-2)+x

Group like terms:

(2x+x)+2=(-x-2)+x

Simplify the arithmetic:

3x+2=(-x-2)+x

Group like terms:

3x+2=(-x+x)-2

Simplify the arithmetic:

3x+2=2

Subtract from both sides:

(3x+2)-2=-2-2

Simplify the arithmetic:

3x=22

Simplify the arithmetic:

3x=4

Divide both sides by :

(3x)3=-43

Simplify the fraction:

x=-43

3. List the solutions

x=0,-43
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=2|x+1|
y=|x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.