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Solution - Absolute value equations

Exact form: k=3,-113
k=3 , -\frac{11}{3}
Mixed number form: k=3,-323
k=3 , -3\frac{2}{3}
Decimal form: k=3,3.667
k=3 , -3.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|k+7|=|4k+8|
without the absolute value bars:

|x|=|y|2|k+7|=|4k+8|
x=+y2(k+7)=(4k+8)
x=y2(k+7)=(4k+8)
+x=y2(k+7)=(4k+8)
x=y2((k+7))=(4k+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|k+7|=|4k+8|
x=+y , +x=y2(k+7)=(4k+8)
x=y , x=y2(k+7)=(4k+8)

2. Solve the two equations for k

15 additional steps

2·(k+7)=(4k+8)

Expand the parentheses:

2k+2·7=(4k+8)

Simplify the arithmetic:

2k+14=(4k+8)

Subtract from both sides:

(2k+14)-4k=(4k+8)-4k

Group like terms:

(2k-4k)+14=(4k+8)-4k

Simplify the arithmetic:

-2k+14=(4k+8)-4k

Group like terms:

-2k+14=(4k-4k)+8

Simplify the arithmetic:

2k+14=8

Subtract from both sides:

(-2k+14)-14=8-14

Simplify the arithmetic:

2k=814

Simplify the arithmetic:

2k=6

Divide both sides by :

(-2k)-2=-6-2

Cancel out the negatives:

2k2=-6-2

Simplify the fraction:

k=-6-2

Cancel out the negatives:

k=62

Find the greatest common factor of the numerator and denominator:

k=(3·2)(1·2)

Factor out and cancel the greatest common factor:

k=3

14 additional steps

2·(k+7)=-(4k+8)

Expand the parentheses:

2k+2·7=-(4k+8)

Simplify the arithmetic:

2k+14=-(4k+8)

Expand the parentheses:

2k+14=4k8

Add to both sides:

(2k+14)+4k=(-4k-8)+4k

Group like terms:

(2k+4k)+14=(-4k-8)+4k

Simplify the arithmetic:

6k+14=(-4k-8)+4k

Group like terms:

6k+14=(-4k+4k)-8

Simplify the arithmetic:

6k+14=8

Subtract from both sides:

(6k+14)-14=-8-14

Simplify the arithmetic:

6k=814

Simplify the arithmetic:

6k=22

Divide both sides by :

(6k)6=-226

Simplify the fraction:

k=-226

Find the greatest common factor of the numerator and denominator:

k=(-11·2)(3·2)

Factor out and cancel the greatest common factor:

k=-113

3. List the solutions

k=3,-113
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=2|k+7|
y=|4k+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.