Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: a=3,-113
a=3 , -\frac{11}{3}
Mixed number form: a=3,-323
a=3 , -3\frac{2}{3}
Decimal form: a=3,3.667
a=3 , -3.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2|a+2||a+7|=0

Add |a+7| to both sides of the equation:

2|a+2||a+7|+|a+7|=|a+7|

Simplify the arithmetic

2|a+2|=|a+7|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|a+2|=|a+7|
without the absolute value bars:

|x|=|y|2|a+2|=|a+7|
x=+y2(a+2)=(a+7)
x=y2(a+2)=((a+7))
+x=y2(a+2)=(a+7)
x=y2((a+2))=(a+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|a+2|=|a+7|
x=+y , +x=y2(a+2)=(a+7)
x=y , x=y2(a+2)=((a+7))

3. Solve the two equations for a

9 additional steps

2·(a+2)=(a+7)

Expand the parentheses:

2a+2·2=(a+7)

Simplify the arithmetic:

2a+4=(a+7)

Subtract from both sides:

(2a+4)-a=(a+7)-a

Group like terms:

(2a-a)+4=(a+7)-a

Simplify the arithmetic:

a+4=(a+7)-a

Group like terms:

a+4=(a-a)+7

Simplify the arithmetic:

a+4=7

Subtract from both sides:

(a+4)-4=7-4

Simplify the arithmetic:

a=74

Simplify the arithmetic:

a=3

12 additional steps

2·(a+2)=(-(a+7))

Expand the parentheses:

2a+2·2=(-(a+7))

Simplify the arithmetic:

2a+4=(-(a+7))

Expand the parentheses:

2a+4=a7

Add to both sides:

(2a+4)+a=(-a-7)+a

Group like terms:

(2a+a)+4=(-a-7)+a

Simplify the arithmetic:

3a+4=(-a-7)+a

Group like terms:

3a+4=(-a+a)-7

Simplify the arithmetic:

3a+4=7

Subtract from both sides:

(3a+4)-4=-7-4

Simplify the arithmetic:

3a=74

Simplify the arithmetic:

3a=11

Divide both sides by :

(3a)3=-113

Simplify the fraction:

a=-113

4. List the solutions

a=3,-113
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=2|a+2|
y=|a+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.