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Solution - Absolute value equations

Exact form: =-53,-133
=-\frac{5}{3} , -\frac{13}{3}
Mixed number form: =-123,-413
=-1\frac{2}{3} , -4\frac{1}{3}
Decimal form: =1.667,4.333
=-1.667 , -4.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|+4|=3|x+3|
without the absolute value bars:

|x|=|y||+4|=3|x+3|
x=+y(+4)=3(x+3)
x=y(+4)=3((x+3))
+x=y(+4)=3(x+3)
x=y(+4)=3(x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||+4|=3|x+3|
x=+y , +x=y(+4)=3(x+3)
x=y , x=y(+4)=3((x+3))

2. Solve the two equations for

7 additional steps

(4)=3·(x+3)

Expand the parentheses:

(4)=3x+3·3

Simplify the arithmetic:

(4)=3x+9

Swap sides:

3x+9=(4)

Subtract from both sides:

(3x+9)-9=(4)-9

Simplify the arithmetic:

3x=(4)-9

Simplify the arithmetic:

3x=5

Divide both sides by :

(3x)3=-53

Simplify the fraction:

x=-53

12 additional steps

(4)=3·(-(x+3))

Expand the parentheses:

(4)=3·(-x-3)

(4)=3·-x+3·-3

Group like terms:

(4)=(3·-1)x+3·-3

Multiply the coefficients:

(4)=-3x+3·-3

Simplify the arithmetic:

(4)=-3x-9

Swap sides:

-3x-9=(4)

Add to both sides:

(-3x-9)+9=(4)+9

Simplify the arithmetic:

-3x=(4)+9

Simplify the arithmetic:

3x=13

Divide both sides by :

(-3x)-3=13-3

Cancel out the negatives:

3x3=13-3

Simplify the fraction:

x=13-3

Move the negative sign from the denominator to the numerator:

x=-133

3. List the solutions

=-53,-133
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|+4|
y=3|x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.