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Solution - Absolute value equations

Exact form:

w = - 7, \frac{4}{5}

w=-7 , \frac{4}{5}

Decimal form:

w = - 7, 0.8

w=-7 , 0.8

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$2 | 4 w - 11 | = 3 | 4 w + 2 |$
without the absolute value bars:

$\| x \| = \| y \|$	$2 \| 4 w - 11 \| = 3 \| 4 w + 2 \|$
$x = + y$	$2 (4 w - 11) = 3 (4 w + 2)$
$x = - y$	$2 (4 w - 11) = 3 (- (4 w + 2))$
$+ x = y$	$2 (4 w - 11) = 3 (4 w + 2)$
$- x = y$	$2 (- (4 w - 11)) = 3 (4 w + 2)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$2 \| 4 w - 11 \| = 3 \| 4 w + 2 \|$
$x = + y$ , $+ x = y$	$2 (4 w - 11) = 3 (4 w + 2)$
$x = - y$ , $- x = y$	$2 (4 w - 11) = 3 (- (4 w + 2))$

2. Solve the two equations for w

19 additional steps

$2 \cdot (4 w - 11) = 3 \cdot (4 w + 2)$

Expand the parentheses:

$2 \cdot 4 w + 2 \cdot - 11 = 3 \cdot (4 w + 2)$

Multiply the coefficients:

$8 w + 2 \cdot - 11 = 3 \cdot (4 w + 2)$

Simplify the arithmetic:

$8 w - 22 = 3 \cdot (4 w + 2)$

Expand the parentheses:

$8 w - 22 = 3 \cdot 4 w + 3 \cdot 2$

Multiply the coefficients:

$8 w - 22 = 12 w + 3 \cdot 2$

Simplify the arithmetic:

$8 w - 22 = 12 w + 6$

Subtract from both sides:

$(8 w - 22) - 12 w = (12 w + 6) - 12 w$

Group like terms:

$(8 w - 12 w) - 22 = (12 w + 6) - 12 w$

Simplify the arithmetic:

$- 4 w - 22 = (12 w + 6) - 12 w$

Group like terms:

$- 4 w - 22 = (12 w - 12 w) + 6$

Simplify the arithmetic:

$- 4 w - 22 = 6$

Add to both sides:

$(- 4 w - 22) + 22 = 6 + 22$

Simplify the arithmetic:

$- 4 w = 6 + 22$

Simplify the arithmetic:

$- 4 w = 28$

Divide both sides by :

$\frac{(- 4 w)}{- 4} = \frac{28}{- 4}$

Cancel out the negatives:

$\frac{4 w}{4} = \frac{28}{- 4}$

Simplify the fraction:

$w = \frac{28}{- 4}$

Move the negative sign from the denominator to the numerator:

$w = \frac{- 28}{4}$

Find the greatest common factor of the numerator and denominator:

$w = \frac{(- 7 \cdot 4)}{(1 \cdot 4)}$

Factor out and cancel the greatest common factor:

$w = - 7$

18 additional steps

$2 \cdot (4 w - 11) = 3 \cdot (- (4 w + 2))$

Expand the parentheses:

$2 \cdot 4 w + 2 \cdot - 11 = 3 \cdot (- (4 w + 2))$

Multiply the coefficients:

$8 w + 2 \cdot - 11 = 3 \cdot (- (4 w + 2))$

Simplify the arithmetic:

$8 w - 22 = 3 \cdot (- (4 w + 2))$

Expand the parentheses:

$8 w - 22 = 3 \cdot (- 4 w - 2)$

Expand the parentheses:

$8 w - 22 = 3 \cdot - 4 w + 3 \cdot - 2$

Multiply the coefficients:

$8 w - 22 = - 12 w + 3 \cdot - 2$

Simplify the arithmetic:

$8 w - 22 = - 12 w - 6$

Add to both sides:

$(8 w - 22) + 12 w = (- 12 w - 6) + 12 w$

Group like terms:

$(8 w + 12 w) - 22 = (- 12 w - 6) + 12 w$

Simplify the arithmetic:

$20 w - 22 = (- 12 w - 6) + 12 w$

Group like terms:

$20 w - 22 = (- 12 w + 12 w) - 6$

Simplify the arithmetic:

$20 w - 22 = - 6$

Add to both sides:

$(20 w - 22) + 22 = - 6 + 22$

Simplify the arithmetic:

$20 w = - 6 + 22$

Simplify the arithmetic:

$20 w = 16$

Divide both sides by :

$\frac{(20 w)}{20} = \frac{16}{20}$

Simplify the fraction:

$w = \frac{16}{20}$

Find the greatest common factor of the numerator and denominator:

$w = \frac{(4 \cdot 4)}{(5 \cdot 4)}$

Factor out and cancel the greatest common factor:

$w = \frac{4}{5}$

3. List the solutions

$w = - 7, \frac{4}{5}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = 2 | 4 w - 11 |$
$y = 3 | 4 w + 2 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for w

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for w

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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